VBA Excel“错误13：类型不匹配” [英] VBA Excel "error 13: type mismatch"

问题描述

我使用这段代码来创建100000个数字（12位独特的随机数字）

I used this code to create 100000 numbers (12 digit unique random numeric numbers )

Sub uniqueramdom()

Const strCharacters As String = "0123456789"

Dim cllAlphaNums As Collection
Dim arrUnqAlphaNums(1 To 60000) As String
Dim varElement As Variant
Dim strAlphaNum As String
Dim AlphaNumIndex As Long
Dim lUbound As Long
Dim lNumChars As Long
Dim i As Long

Set cllAlphaNums = New Collection
lUbound = UBound(arrUnqAlphaNums)
lNumChars = Len(strCharacters)

On Error Resume Next
Do
    strAlphaNum = vbNullString
    For i = 1 To 12
        strAlphaNum = strAlphaNum & Mid(strCharacters, Int(Rnd() * lNumChars) + 1, 1)
    Next i
    cllAlphaNums.Add strAlphaNum, strAlphaNum
Loop While cllAlphaNums.Count < lUbound
On Error GoTo 0

For Each varElement In cllAlphaNums
    AlphaNumIndex = AlphaNumIndex + 1
    arrUnqAlphaNums(AlphaNumIndex) = varElement
Next varElement

Range("A1").Resize(lUbound).Value = Application.Transpose(arrUnqAlphaNums)

Set cllAlphaNums = Nothing
Erase arrUnqAlphaNums

End Sub

它适用于： Dim arrUnqAlphaNums（1 to 50000）As字符串

但是使用： Dim arrUnqAlphaNums（1 To 100000）As String 不工作并产生错误：类型不匹配

But with:     Dim arrUnqAlphaNums(1 To 100000) As String , it not working and producing Error : type mismatch

我在这里有以下代码 http://www.excelforum.com/

推荐答案

你已经达到了转置的限制。以下将会工作

you have hit the limitation of Transpose. the below would work

Dim arrUnqAlphaNums(1 To 65536 ) As String 'remember the number 65536?

这不会工作

Dim arrUnqAlphaNums(1 To 65537 ) As String 

你会发现这个限制继承自以前版本的Excel的范围。微软可能已经有一些业务不完整

You will find that this limitation inherited on ranges from prior versions of Excel. Microsoft may have left some business incomplete

您可能会重构代码如下

Option Explicit
Sub uniqueramdom()

    Const strCharacters As String = "0123456789"

    Dim strAlphaNum As String
    Dim AlphaNumIndex As Long
    Dim lUbound As Long
    Dim lNumChars As Long
    Dim i As Long
    Dim iRow As Long
    iRow = 1

    lUbound = 100000 'Change here your ubound. This can increase execution time.
    lNumChars = Len(strCharacters)

    On Error Resume Next
    Do
        strAlphaNum = vbNullString
        For i = 1 To 12
            strAlphaNum = strAlphaNum & Mid(strCharacters, Int(Rnd() * lNumChars) + 1, 1)
        Next i
        Cells(iRow, 1) = strAlphaNum
        iRow = iRow + 1
    Loop While iRow <= lUbound
    On Error GoTo 0


End Sub

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