javascript - 怎么获取重复的数据

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本文介绍了javascript - 怎么获取重复的数据的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

问 题

数据是这样的

var  node=[
            {
                "listId":10,
                "projectName":"中行",
                "projectVersion":"0.1.2.0"
            },
             {
                "listId":10,
                "projectName":"中行",
                "projectVersion":"0.1.2.0"
            },
             {
                "listId":10,
                "projectName":"中行",
                "projectVersion":"0.1.2.0"
            },
             {
                "listId":10,
                "projectName":"中行",
                "projectVersion":"0.1.2.0"
            },
            {
                "listId":2,
                "projectName":"公司",
                "projectVersion":"1.1.2.0"
            },
            {
                "listId":3,
                "projectName":"学校",
                "projectVersion":"2.1.1.0"
            },
            {
                "listId":4,
                "projectName":"家",
                "projectVersion":"3.1.2.0"
            },
            {
                "listId":5,
                "projectName":"朋友",
                "projectVersion":"4.1.2.0"
            },
            {
                "listId":6,
                "projectName":"啦啦啦",
                "projectVersion":"5.1.2.0"
            },
            {
                "listId":7,
                "projectName":"哈哈哈",
                "projectVersion":"6.1.2.0"
            },
            {
                "listId":8,
                "projectName":"嘻嘻嘻",
                "projectVersion":"7.1.2.0"
            }
        ];

需要最后得到新的数据

[
            {
                "listId":10,
                "projectName":"中行",
                "projectVersion":"0.1.2.0"
            },
             {
                "listId":10,
                "projectName":"中行",
                "projectVersion":"0.1.2.0"
            },
             {
                "listId":10,
                "projectName":"中行",
                "projectVersion":"0.1.2.0"
            },
             {
                "listId":10,
                "projectName":"中行",
                "projectVersion":"0.1.2.0"
            }]

解决方案

我是先计数,然后再处理
//计数处理

            let opt={};
            let namePP="";
            node.forEach(function(el,index){
              if(!opt[el.projectName]){
                opt[el.projectName] = 1;
            }else{
                opt[el.projectName] += 1;
            }
            if(opt[el.projectName]>1){
                namePP = el.projectName
             }
           })
            let optionsarr=node.filter(function(item){ if(item.projectName == namePP){ return true}})

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