默认Django的Ajax的上传与S3后端给MalformedXML错误 [英] Default django-ajax-uploader with s3 backend gives MalformedXML error
问题描述
我成立了一个测试脚本几乎完全一样在这里的例子： https://github.com/GoodCloud/django-ajax-uploader
这似乎开始上传文件（JavaScript的更新名和文件大小），但鉴于给了我一个500错误与此消息。我无法找到如何解决这事。
S3ResponseError：S3ResponseError：400错误的请求
＆LT;错误＆GT;＆LT; code取代; MalformedXML＆LT; / code＆GT;＆LT;消息＆gt;而没有良好的您提供的XML或没有验证对我们公布schema</Message><RequestId>26E6EF8296A0E585</RequestId><HostId>F4QUOsVT4LxC+6OUP2lE1/9uPC77keOejyWs57GpS5kjvHXpun3U+81ntL8ZTgDa</HostId></Error>
我能上传文件的外壳，这里使用的命令博托： 上传0字节的文件到Amazon S3
视图：
从ajaxuploader.views进口AjaxFileUploader
从ajaxuploader.backends.s3进口S3UploadBackend
import_uploader = AjaxFileUploader（后端= S3UploadBackend）
JavaScript的：
VAR上传=新qq.FileUploader（{
动作：/ AJAX / profile文件上传/，
元素：$（'＃文件上传'）[0]，
多：真，
的onComplete：功能（ID，文件名，responseJSON）{
如果（responseJSON.success）{
警报（成功！）;
} 其他 {
警报（上传失败！）;
}
}，
onAllComplete：功能（上传）{
//上传是地图数组
//地图是这样的：{文件：文件对象，响应：JSONServerResponse}
警报（全部完成！）;
}，
PARAMS：{
csrf_token'。$（'[NAME = csrfmiddlewaretoken]）VAL（）
csrf_name'：'csrfmiddlewaretoken，
csrf_xname'：'X-CSRFToken'，
}，
}）;
模板：
＆LT; DIV ID =文件上传＆GT;
＆LT; NOSCRIPT＆GT;
＆LT; P＆gt;请启用JavaScript才能使用文件上传＆LT; / P＆GT;
＆LT; / NOSCRIPT＆GT;
＆LT; / DIV＆GT;
我在settings.py文件中的S3访问变量（他们被称为在ajaxuploader /后端/ s3.py文件）：
AWS_ACCESS_KEY_ID = myAccessKey
AWS_SECRET_ACCESS_KEY = mySecretKey
AWS_BUCKET_NAME = bucketName
我解决了这个问题，一个自定义的S3后端的覆盖上传功能和安培;使用Django的存储器，而不是博托保存文件。试试这个：
从ajaxuploader.backends.base进口AbstractUploadBackend
从django.core.files.storage进口default_storage
类S3CustomUpload（AbstractUploadBackend）：
NUM_PARALLEL_PROCESSES = 4
高清upload_chunk（个体经营，分块）：
#save文件到S3
self._fd.write（块）
self._fd.close（）
DEF设置（个体经营，文件名）：
self._fd = default_storage.open（'％S /％s的％（上传/材料/'，STR（文件名）），世行）
高清上传（个体经营，上传，文件名，raw_data，*的args，** kwargs）：
尝试：
如果raw_data：
＃文件是通过AJAX上传，并流研究。
块= uploaded.read（self.BUFFER_SIZE）
而LEN（块）＆GT; 0：
self.upload_chunk（块，*的args，** kwargs）
块= uploaded.read（self.BUFFER_SIZE）
其他：
＃文件是通过POST上传的，而且是在这里。
对于大块uploaded.chunks（）：
self.upload_chunk（块，*的args，** kwargs）
返回True
除：
＃事情进展得很厉害。
返回False
高清upload_complete（个体经营，要求，文件名，*的args，** kwargs）：
上传=上传（）
upload.upload = settings.S3_URL +上传/材料/+文件名
upload.name =文件名
upload.save（）
返回{'PK'：upload.pk}
I set up a test script almost exactly like in the example here: https://github.com/GoodCloud/django-ajax-uploader
It seems to start uploading the file (javascript updates the name and size of the file), but the view gives me a 500 error with this message. I can't find anything on how to fix it.
S3ResponseError: S3ResponseError: 400 Bad Request
<Error><Code>MalformedXML</Code><Message>The XML you provided was not well-formed or did not validate against our published schema</Message><RequestId>26E6EF8296A0E585</RequestId><HostId>F4QUOsVT4LxC+6OUP2lE1/9uPC77keOejyWs57GpS5kjvHXpun3U+81ntL8ZTgDa</HostId></Error>
I was able to upload a file in the shell with boto using the commands here: Upload 0 byte file to Amazon S3
The view:
from ajaxuploader.views import AjaxFileUploader
from ajaxuploader.backends.s3 import S3UploadBackend
import_uploader = AjaxFileUploader(backend=S3UploadBackend)
javascript:
var uploader = new qq.FileUploader({
action: "/ajax/profile-upload/",
element: $('#file-uploader')[0],
multiple: true,
onComplete: function(id, fileName, responseJSON) {
if(responseJSON.success) {
alert("success!");
} else {
alert("upload failed!");
}
},
onAllComplete: function(uploads) {
// uploads is an array of maps
// the maps look like this: {file: FileObject, response: JSONServerResponse}
alert("All complete!");
},
params: {
'csrf_token': $('[name=csrfmiddlewaretoken]').val(),
'csrf_name': 'csrfmiddlewaretoken',
'csrf_xname': 'X-CSRFToken',
},
});
template:
<div id="file-uploader">
<noscript>
<p>Please enable JavaScript to use file uploader.</p>
</noscript>
</div>
I have the s3 access variables in my settings.py file (they are called in the ajaxuploader/backends/s3.py file):
AWS_ACCESS_KEY_ID = myAccessKey
AWS_SECRET_ACCESS_KEY = mySecretKey
AWS_BUCKET_NAME = bucketName
I solved this problem with a custom s3 backend that override the upload function & use django-storages instead of boto to save files. try this :
from ajaxuploader.backends.base import AbstractUploadBackend
from django.core.files.storage import default_storage
class S3CustomUpload(AbstractUploadBackend):
NUM_PARALLEL_PROCESSES = 4
def upload_chunk(self, chunk):
#save file to s3
self._fd.write(chunk)
self._fd.close()
def setup(self, filename):
self._fd = default_storage.open('%s/%s' % ('uploads/materials/', str(filename)), 'wb')
def upload(self, uploaded, filename, raw_data, *args, **kwargs):
try:
if raw_data:
# File was uploaded via ajax, and is streaming in.
chunk = uploaded.read(self.BUFFER_SIZE)
while len(chunk) > 0:
self.upload_chunk(chunk, *args, **kwargs)
chunk = uploaded.read(self.BUFFER_SIZE)
else:
# File was uploaded via a POST, and is here.
for chunk in uploaded.chunks():
self.upload_chunk(chunk, *args, **kwargs)
return True
except:
# things went badly.
return False
def upload_complete(self, request, filename, *args, **kwargs):
upload = Upload()
upload.upload = settings.S3_URL + "uploads/materials/"+ filename
upload.name = filename
upload.save()
return {'pk': upload.pk}
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