javascript - jquery 如何取出一组元素中的 data-url？
本文介绍了javascript - jquery 如何取出一组元素中的 data-url？的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
问 题
我想取出每个url 给他绑定事件实现跳转，不要用a标签！如何做？
为什么取不到属性值？
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<meta http-equiv="X-UA-Compatible" content="IE=edge">
<title></title>
<link rel="stylesheet" href="">
</head>
<body>
<ul>
</ul>
</body>
<script src="http://apps.bdimg.com/libs/jquery/2.1.4/jquery.min.js" type="text/javascript" charset="utf-8"></script>
<script src="http://apps.bdimg.com/libs/fastclick/1.0.0/fastclick.min.js" type="text/javascript" charset="utf-8" ></script>
<script type="text/javascript" charset="utf-8" >
var DATA='[{"status": "IN_PROGRESS", "loan_limited": "5", "load_no": "123131231", "agreement": "http://www.mop.com/", "payed": "1", "amount": 15000.14885, "loan_time": "2016-06-17"}, {"status": "DONE", "loan_limited": "1", "load_no": "123131123131231", "agreement": "http://www.163.com/", "payed": "1", "amount": 15000, "loan_time": "2016-05-17"}, {"status": "IN_PROGRESS", "loan_limited": "5", "load_no": "123131231231", "agreement": "http://www.baidu.com/", "payed": "1", "amount": 25000, "loan_time": "2016-06-10"}]';
var DATA=DATA.replace(/(\d{4})-(\d{2})-(\d{2})/g, '$1年$2月$3日');
//console.log(DATA);
var dataJSON=JSON.parse(DATA);
var sort=dataJSON.sort(function(a,b){
return a.status>b.status?-1:1
});
var template="<li class= $status$ ><div><p>借款金额</p><p>$amount$</p><p > $status$ </p></div>"
+"<div><p>借款日</p><p>$loan_time$</p></div>"
+"<div><p>还款期限</p><p>$loan_limited$</p></div>"
+"<div><p>已还</p><p>$payed$</p></div>"
+"<div><p>借款编号</p><p>$load_no$</p><p class='test' data-url=$agreement$>《借款协议》</p></div></li>"
dataJSON.forEach(function(item){
var tplReplace=template.replace("$amount$",function(num){
var num=item.amount;
var num = (num || 0).toString(), result = '';
while (num.length > 3) {
result = ',' + num.slice(-3) + result;
num = num.slice(0, num.length - 3);
}
if (num) { result = num + result; }
return result
})
.replace("$status$",item.status.toLowerCase())
.replace("$status$",function(){
if(item.status=="IN_PROGRESS"){
return "进行中"
}
else{
return "已完结"
}
})
.replace("$loan_time$",item.loan_time)
.replace("$loan_limited$",item.loan_limited)
.replace("$payed$",item.payed)
.replace("$agreement$",item.agreement)
.replace("$load_no$",item.load_no);
$("ul").append(tplReplace);
})
$(".test").bind("click", function(){
console.log($(this).data('url'));
alert("!!!!");
window.location.href = $(this).data('url');
})
</script>
</html>解决方案
$(test[i]).data("url")这篇关于javascript - jquery 如何取出一组元素中的 data-url？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
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