根据另一列中的值,在多列中填充和关闭单元格 [英] Fill up and down cells in multiple columns based on values in another column

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本文介绍了根据另一列中的值,在多列中填充和关闭单元格的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有以下列和值:

 开始时间其他值名字姓氏其他信息
5041 * value1 info1
5041 * value2 firstname1 lastname1 info2
13089 value3 info3
16130 value4 info4
26391 * value5 info5
26391 * value6 info6
26391 * value7 firstname2 lastname2 info7
27878 value8 info8
27878 value9 info9
28234 value10 info10
63189 * value11 info11
63189 * value12 info12
63189 * value13 info13
63189 * value14 firstname3 lastname3 info14
64335 value15 info15
65423 value16 info16
72089 * value17 info17
72089 * value18 firstname4 lastname4 info18
73495 value19 info19
73495 value20 info20
74330 value21 info21
74877 value22 info22
76710 value23 info23
82599 * value24 info24
82599 * value25 firstname5 lastname5 info25
98712 * value26 info26
98712 * value27 firstname6 lastname6 info27
98725 value28 info28
100605 value29 info29
1006 05 value30 info30
100954 value31 info31




我希望这样:

 开始时间其他值名字姓氏其他信息
5041 value1 firstname1 lastname1 info1
5041 value2 firstname1 lastname1 info2
13089 value3 firstname1 lastname1 info3
16130 value4 firstname1 lastname1 info4
26391 value5 firstname2 lastname2 info5
26391 value6 firstname2 lastname2 info6
26391 value7 firstname2 lastname2 info7
27878 value8 firstname2 lastname2 info8
27878 value9 firstname2 lastname2 info9
28234 value10 firstname2 lastname2 info10
63189 value11 firstname3 lastname3 info11
63189 val ue12 firstname3 lastname3 info12
63189 value13 firstname3 lastname3 info13
63189 value14 firstname3 lastname3 info14
64335 value15 firstname3 lastname3 info15
65423 value16 firstname3 lastname3 info16
72089 value17 firstname4 lastname4 info17
72089 value18 firstname4 lastname4 info18
73495 value19 firstname4 lastname4 info19
73495 value20 firstname4 lastname4 info20
74330 value21 firstname4 lastname4 info21
74877 value22 firstname4 lastname4 info22
76710 value23 firstname4 lastname4 info23
82599 value24 firstname5 lastname5 info24
82599 value25 firstname5 lastname5 info25
98712 value26 firstname6 lastname6 info26
98712 value27 firstname6 lastname6 inf o27
98725 value28 firstname6 lastname6 info28
100605 value29 firstname6 lastname6 info29
100605 value30 firstname6 lastname6 info30
100954 value31 firstname6 lastname6 info31
pre>




我使用以下代码感谢@Jeeped's answer

  Sub FillColBlanksSpecial2()

Dim wks As Worksheet
Dim rng As Range
Dim rng2 As范围
Dim blnk As Range
Dim LastRow As Long
Dim col As Long
Dim lRows As Long
Dim lLimit As Long

Dim lCount As Long
错误恢复下一步

lRows = 2
lLimit = 1000

设置wks = ActiveSheet
对于工作表中的每个wks
如果Ri ght(wks.Name,2)=-A或右(wks.Name,2)=-B然后
用wks
带.Cells(1,1).CurrentRegion
与.Columns(C:D)
如果CBool​​(Application.CountBlank(.Cells))然后
对于每个blnk在.SpecialCells(xlCellTypeBlanks)
blnk.FormulaR1C1 = = if(countifs(r1c1:r [-1] c1,rc1,r1c:r [-1] c, - ),index(r1c:r [-1] c,match(rc1, r1c1:r [-1] c1,0)),if(countifs(r [1] c1:r9999c1,rc1,r [1] c:r9999c, - ] c:r9999c,match(rc1,r [1] c1:r9999c1,0)),r [-1] c))
blnk.Value = blnk.Value
下一个blnk
结束如果
结束
结束
结束
结束如果
下一个wks
结束Sub




使用xlR1C1风格的公式和它的xlA1等价物:

  = IF(COUNTIFS(R1C1:R [-1] C1,RC1,R1C: R [-1] C, - ),INDEX(R1C:R [-1] C,MATCH(RC1,R1C1:R [-1] C1,0)),IF ] C1:R9999C1,RC1,R [1] C:R9999C, - ),INDEX(R [1] C:R9999C,MATCH(RC1,R [1] C1:R9999C1,0)),R [-1] C))
= IF(COUNTIFS($ A $ 1:$ A1,$ A2,C $ 1:C1,),INDEX(C $ 1:C1,MATCH ,$ A $ 1:$ A1,0)),IF(COUNTIFS($ A3:$ A $ 9999,$ A2,C3:C $ 9999,),INDEX(C3:C $ 9999,MATCH ,$ A3:$ A $ 9999,0)),C1))




目标是根据条件 C:D 填充现有值:

1。以 C:D 中的值填充,直到相同列中的下一个非空单元格(这些非空单元格包含唯一值firstname1,firstname2等)
< BR> 2。取 C:D 中的值,并填写向上,如果上面的空行在列A 中具有相同的值,其行在下面,我们正在处理的价值。



@ Jeeped的答案正常工作:

它需要列 C:D ,并填写空行,直到包含新值的下一行;如果该空行在列 A 中共享相同的值,那么它还会填满一个空行,下面的行包含要复制的值。




,但只有填写一行。我的示例数据(以下链接)显示可能有 多个空行 在包含需要填写的列 C:D 中的值的行之上。



如何修改此vba代码以适应此条件?



这是具有较长示例数据的excel工作表。该工作簿包含两个表格:我有什么&



PS 除了第一列中的代码之外的星号除外视觉可访问性的目的是识别在列 A 中共享相同值的空行与下面的行具有列 C:D 中的值;否则它们不会出现在原始数据表中。




通过空行,我的意思是那些没有列 C:D 中的值。

解决方案

我已经对公式进行了更多的复杂化,以实现垂直查找到多个列。需要修改的单行是所有嵌套代码的中心。

  blnk.FormulaR1C1 == if(countifs r1c1:r [-1] c1,rc1,r1c:r [-1] c, - ),索引(r1c:r [-1] c,match(rc1,r1c1: 1] c1,0)),if(countifs(r [1] c1:r9999c1,rc1,r [1] c:r9999c, - ),index(r [1] c:r9999c,分钟(指数(行(R:r9998あ)行(R [-1])+((R [1] C1:r9999c1<> RC1)+未(LEN(R [1] C:r9999c)))* 1e + 99,,))),r [-1] c))

一个xlA1风格的公式,如下所示(从C2看到)。

  = IF(COUNTIFS($ A $ 1:$ A1, (A2 $,A $ 1:$ A1,0)),IF(COUNTIFS($ A3:$ A $ 9999,$ A $,C $ 1:C1,& $ A2,C3:C $ 9999,),INDEX(C3:C $ 9999,MIN(INDEX(ROW(2:$ 9998)-ROW(1:1)+(($ A3:$ A $ 9999< ; $ A2)+ NOT(LEN(C3:C $ 9999)))* 1E + 99,,))),C1))

请注意,编码公式需要将带引号的字符串中的引号加倍。


I have the following columns and values:

Begin Time  Other values    First Name  Last Name   other info
5041*       value1                                  info1
5041*       value2          firstname1  lastname1   info2
13089       value3                                  info3
16130       value4                                  info4
26391*      value5                                  info5
26391*      value6                                  info6
26391*      value7          firstname2  lastname2   info7
27878       value8                                  info8
27878       value9                                  info9
28234       value10                                 info10
63189*      value11                                 info11
63189*      value12                                 info12
63189*      value13                                 info13
63189*      value14         firstname3  lastname3   info14
64335       value15                                 info15
65423       value16                                 info16
72089*      value17                                 info17
72089*      value18         firstname4  lastname4   info18
73495       value19                                 info19
73495       value20                                 info20
74330       value21                                 info21
74877       value22                                 info22
76710       value23                                 info23
82599*      value24                                 info24
82599*      value25          firstname5 lastname5   info25
98712*      value26                                 info26
98712*      value27          firstname6 lastname6   info27
98725       value28                                 info28
100605      value29                                 info29
100605      value30                                 info30
100954      value31                                 info31


I expect this:

Begin Time  Other values    First Name  Last Name   other info
5041        value1          firstname1  lastname1   info1
5041        value2          firstname1  lastname1   info2
13089       value3          firstname1  lastname1   info3
16130       value4          firstname1  lastname1   info4
26391       value5          firstname2  lastname2   info5
26391       value6          firstname2  lastname2   info6
26391       value7          firstname2  lastname2   info7
27878       value8          firstname2  lastname2   info8
27878       value9          firstname2  lastname2   info9
28234       value10         firstname2  lastname2   info10
63189       value11         firstname3  lastname3   info11
63189       value12         firstname3  lastname3   info12
63189       value13         firstname3  lastname3   info13
63189       value14         firstname3  lastname3   info14
64335       value15         firstname3  lastname3   info15
65423       value16         firstname3  lastname3   info16
72089       value17         firstname4  lastname4   info17
72089       value18         firstname4  lastname4   info18
73495       value19         firstname4  lastname4   info19
73495       value20         firstname4  lastname4   info20
74330       value21         firstname4  lastname4   info21
74877       value22         firstname4  lastname4   info22
76710       value23         firstname4  lastname4   info23
82599       value24         firstname5  lastname5   info24
82599       value25         firstname5  lastname5   info25
98712       value26         firstname6  lastname6   info26
98712       value27         firstname6  lastname6   info27
98725       value28         firstname6  lastname6   info28
100605      value29         firstname6  lastname6   info29
100605      value30         firstname6  lastname6   info30
100954      value31         firstname6  lastname6   info31


I am using the following code thanks to @Jeeped's answer

Sub FillColBlanksSpecial2()

    Dim wks As Worksheet
    Dim rng As Range
    Dim rng2 As Range
    Dim blnk As Range
    Dim LastRow As Long
    Dim col As Long
    Dim lRows As Long
    Dim lLimit As Long

    Dim lCount As Long
    On Error Resume Next

    lRows = 2
    lLimit = 1000

    Set wks = ActiveSheet
    For Each wks In Worksheets
        If Right(wks.Name, 2) = "-A" Or Right(wks.Name, 2) = "-B" Then
            With wks
                With .Cells(1, 1).CurrentRegion
                    With .Columns("C:D")
                        If CBool(Application.CountBlank(.Cells)) Then
                            For Each blnk In .SpecialCells(xlCellTypeBlanks)
                                blnk.FormulaR1C1 = "=if(countifs(r1c1:r[-1]c1, rc1, r1c:r[-1]c, ""<>""), index(r1c:r[-1]c, match(rc1, r1c1:r[-1]c1, 0)), if(countifs(r[1]c1:r9999c1, rc1, r[1]c:r9999c, ""<>""), index(r[1]c:r9999c, match(rc1, r[1]c1:r9999c1, 0)), r[-1]c))"
                                blnk.Value = blnk.Value
                            Next blnk
                        End If
                    End With
                End With
            End With
        End If
    Next wks
End Sub


with the formula in xlR1C1 style and its xlA1 equivalent:

=IF(COUNTIFS(R1C1:R[-1]C1, RC1, R1C:R[-1]C, "<>"), INDEX(R1C:R[-1]C, MATCH(RC1, R1C1:R[-1]C1, 0)), IF(COUNTIFS(R[1]C1:R9999C1, RC1, R[1]C:R9999C, "<>"), INDEX(R[1]C:R9999C, MATCH(RC1, R[1]C1:R9999C1, 0)), R[-1]C))
=IF(COUNTIFS($A$1:$A1, $A2, C$1:C1, "<>"), INDEX(C$1:C1, MATCH($A2, $A$1:$A1, 0)), IF(COUNTIFS($A3:$A$9999, $A2, C3:C$9999, "<>"), INDEX(C3:C$9999, MATCH($A2, $A3:$A$9999, 0)), C1))



The goal is to fill up and down the columns C:D with the existing values based on the conditions:
1. Take the values in C:D and fill down until the next non-empty cell in the same columns.(these non-empty cells contain unique values, firstname1, firstname2, etc)
2. Take the values in C:D and fill up if the empty row(s) above share the same value in Column A with the row which is below and whose values we are coping up.

@Jeeped's answer is working correctly:
it takes the values from columns C:D and fills down the empty rows until the next row that contains new values; it also fills up one empty row if the that empty row shares the same value in column A with the row below that contains the to-be-copied values.


but it only fills up one row. My example data (link below) shows that there might be more than one empty row above the rows that contain values in column C:D that need to be filled up.

How to modify this vba code to accommodate this condition?

Here is the excel worksheet with a longer example data. The workbook contains two sheets: what I have & what I expect.

P.S. the asterisk mark besides the codes in first column are solely for the purpose of the visual accessibility to identify the empty rows that share the same value in column A with the row below that has values in columns C:D; otherwise they don't appear in the original data sheet.


By empty row, I mean those rows which don't have values in columns C:D.

解决方案

I've complicated the formula a bit more to achieve the vertical lookup to more than a single column. The single line that needs modification is in the center of all the nested code.

blnk.FormulaR1C1 = "=if(countifs(r1c1:r[-1]c1, rc1, r1c:r[-1]c, ""<>""), index(r1c:r[-1]c, match(rc1, r1c1:r[-1]c1, 0)), if(countifs(r[1]c1:r9999c1, rc1, r[1]c:r9999c, ""<>""), index(r[1]c:r9999c, min(index(row(r:r9998)-row(r[-1])+((r[1]c1:r9999c1<>rc1)+not(len(r[1]c:r9999c)))*1e+99, , ))), r[-1]c))"

That translates to an xlA1 style formula like the following (as seen from C2).

=IF(COUNTIFS($A$1:$A1, $A2, C$1:C1, "<>"), INDEX(C$1:C1, MATCH($A2, $A$1:$A1, 0)), IF(COUNTIFS($A3:$A$9999, $A2, C3:C$9999, "<>"), INDEX(C3:C$9999, MIN(INDEX(ROW(2:$9998)-ROW(1:1)+(($A3:$A$9999<>$A2)+NOT(LEN(C3:C$9999)))*1E+99, , ))), C1))

Note that the coded formula requires doubling up the quotes within the quoted string.

这篇关于根据另一列中的值,在多列中填充和关闭单元格的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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