Excel forumla:CountifS +多个条件+不同的计数 [英] Excel forumla : CountifS + multiple criteria + distinct count
问题描述
Countifs()做,但不包括不同的计数...
这里有一个例子。
我有一个表,我想计算满足多个条件的不同项目(列项)数量A和B:A> 2和B< 5。
行项目ColA ColB
1 QQQ 3 4
2 QQQ 3 3
3 QQQ 5 4
4 TTT 4 4
5 TTT 2 3
6 TTT 0 1
7 XXX 1 2
8 XXX 5 3
9 zzz 1 9
Countifs的工作方式如下:COUNTIFS([ColumnA],criteria A, ColumnB],标准B)
COUNTIFS([ColumnA],> 2,[ColumnB],< 5)
返回:行1,2,4,5,8 => Count = 5
如何根据项目列添加一个不同的计数功能:
行1,2在一个唯一的项目上QQQ 第4行是独一无二的项目TTT
第8行是唯一的项目XXX
返回Count = 3
如何计数3?
谢谢
您可以下载excel文件@ Excel文件
丑陋的公式,但它的作品。
= SUM(((FREQUENCY(IF(C2:C10> 2,1,0))* IF(D2:D10 < 0)*(COUNTIF(B2:B10, > 中&安培; B2:B10)+1),ROW(B2:B10)-ROW(B2)))*(ROW(B2:B11)-ROW(B2) )> 0)* 1)
我将从标准IFS开始:
(B2:D10< 5,1,0)/ code>
为满足两个条件的行提供1和0的数组。对于您的示例,ARRAY = {1; 1; 1; 1; 0; 0; 0; 1; 0}
其中B2:B10是Item列, COUNTYF(B2:B10,>& B2:B10)
返回{6; 6; 6; 3; 3; 3; 1; 1; 0}其中数字等于项目数价值B2:B10字母小于测试项目值。
- QQQ转到6 [3TTT,2XXX 1zzz]
- TTT转到3 [2XXX,1zzz]
- XXX转到1 [1zzz ]
- zzz转到0 [0小于zzz]
需要添加1到此数组,以确保没有0值:
{7; 7; 7; 4; 4; 4; 2; 2; 1}
所以当乘以标准和countif语句:
(IF(C2:C10> 2,1,0 )* IF(D2:D10 <5,1,0)*(COUNTIF(B2:B10,>& B2:B10)+1)
您可以得到ARRAY = {7; 7; 7; 4; 0; 0; 0; 2; 0}
FREQUENCY(ARRAY,ROW(B2:B10)-ROW(B2))
/ pre>
ROW(B2:B10)-ROW(B2)将频率仓设置为{0; 1; 2; 3; 4; 5; 6; 7; 8}。因此,频率公式的输出是{4; 0; 1; 0; 1; 0; 0; 3; 0; 0},其中最后0是大于8的所有值。
((ROW(B2:B11)-ROW(B2)> 0)* 1)等于{0; 1; 1; 1; 1; 1; 1; 1; 1; 1}。将ARRAY乘以此将在开始时消除0计数:ARRAY = {0; 0; 1; 0; 1; 0; 0; 3; 0; 0}。 [注意:B11是最低项目列单元格+ 1,因为从超过8的值的频率公式中添加的数组值]
(ARRAY)> 0)* 1 = {0; 0; 1; 0; 1; 0; 0; 1; 0; 0}
SUM this = 3。
ctrl + shift + enter,因为它是一个数组公式。
cmd + shift + enter for mac。
I'm looking for a formula calculating : distinct Count + multiple criteria Countifs() does it but do not includes distinct count...
Here is an example.
I have a table on which I want to count the number of distinct items (column item) satisfying multiple conditions one column A and B : A>2 and B<5.
Line Item ColA ColB 1 QQQ 3 4 2 QQQ 3 3 3 QQQ 5 4 4 TTT 4 4 5 TTT 2 3 6 TTT 0 1 7 XXX 1 2 8 XXX 5 3 9 zzz 1 9
Countifs works this way : COUNTIFS([ColumnA], criteria A, [ColumnB], criteria B)
COUNTIFS([ColumnA], > 2 , [ColumnB], < 5)
Returns : lines 1,2,4,5,8 => Count = 5
How can I add a distinct count function based on the Item Column ? :
lines 1,2 are on a unique item QQQ
lines 4,5 are on a unique item TTT
Line 8 is on a unique item XXX
Returns Count = 3
How can I count 3 ?!
Thanks
You can download the excel file @ Excel file
解决方案Ugly formula, but it works.
=SUM(((FREQUENCY(IF(C2:C10>2,1,0)*IF(D2:D10<5,1,0)*(COUNTIF(B2:B10,">"&B2:B10)+1),ROW(B2:B10)-ROW(B2)))*(ROW(B2:B11)-ROW(B2))>0)*1)
I'll start with the criteria IFS:
IF(C2:C10>2,1,0)*IF(D2:D10<5,1,0)
Gives an array of 1s and 0s for the rows that satisfy both criteria. ARRAY = {1;1;1;1;0;0;0;1;0} for your example.
Where B2:B10 is the Item column, the countif formula:
COUNTIF(B2:B10,">"&B2:B10)
returns {6;6;6;3;3;3;1;1;0} where the number equals the number of item values in B2:B10 alphabetically less than the tested item value.
- QQQ goes to 6 [3"TTT", 2"XXX", 1"zzz"]
- TTT goes to 3 [2"XXX", 1"zzz"]
- XXX goes to 1 [1"zzz"]
- zzz goes to 0 [0 less than "zzz"]
Need to add 1 to this array to make sure there are no 0 values: {7;7;7;4;4;4;2;2;1}.
So when multiplying the criteria, and the countif statement:
(IF(C2:C10>2,1,0)*IF(D2:D10<5,1,0)*(COUNTIF(B2:B10,">"&B2:B10)+1)
You get ARRAY = {7;7;7;4;0;0;0;2;0}.
FREQUENCY(ARRAY,ROW(B2:B10)-ROW(B2))
ROW(B2:B10)-ROW(B2) sets the frequency bins to {0;1;2;3;4;5;6;7;8}. So the output of the frequency formula is {4;0;1;0;1;0;0;3;0;0} where the last 0 is for all values greater than 8.
((ROW(B2:B11)-ROW(B2)>0)*1) equals {0;1;1;1;1;1;1;1;1;1}. Multiplying ARRAY by this removes the 0 count at the start: ARRAY = {0;0;1;0;1;0;0;3;0;0}. [NOTE: B11 is lowest item column cell+1 because of the added array value from the frequency formula for values over 8]
(ARRAY)>0)*1 = {0;0;1;0;1;0;0;1;0;0}
SUM this = 3.
ctrl + shift + enter, because it's an array formula.
cmd + shift + enter for mac.
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