捕捉“堆栈溢出”递归C ++函数中的异常 [英] Catching "Stack Overflow" exceptions in recursive C++ functions

问题描述

可以在递归C ++函数中捕获堆栈溢出异常吗？如果是这样，那么如何？

Is it possible to catch a stack overflow exception in a recursive C++ function? If so, how?

所以在这种情况下会发生什么

so what will happen in this case

void doWork()
{

     try() {

     doWork();    
     }


     catch( ... )  {

     doWork();    
     }
}  

我不是在寻找具体操作系统的答案。一般来说

I am not looking for an answer to specific OS. Just in general

推荐答案

实际上没有便携式方式。当控制递归函数尝试在堆栈地址空间之外分配堆栈帧时，通常会导致无效的存储器访问。这通常会根据操作系统崩溃您的程序与分段故障/访问冲突。换句话说，它不会抛出一个可以通过语言以标准方式处理的c ++异常。

There's really no portable way to do it. An out of control recursive function will usually cause an invalid memory access when it tries to allocate a stack frame beyond the stack address space. This will usually just crash your program with a Segmentation Fault/Access Violation depending on the OS. In other words, it won't throw a c++ exception that can be handled in a standard way by the language.

这篇关于捕捉“堆栈溢出”递归C ++函数中的异常的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！