如何可靠地识别PHP中的特定错误？ [英] How can I reliably identify a specific error in PHP?

问题描述

由于PHP的 unlink（）本身不支持异常，我正在为其创建一个包装函数。它应该抛出一个 FileNotFoundException ，如果，那么给定的文件不能被删除，因为它不存在。

Because of PHP's unlink() not supporting exceptions natively, I'm making a wrapper function for it. It should throw a FileNotFoundException if, well, the given file could not be deleted because it doesn't exist.

为此，我需要确定由 unlink（）抛出的错误是由缺少的文件或其他内容引起的。

For this, I need to determine whether the error thrown by unlink() was caused by a missing file or something else.

这是我自定义删除功能的测试版本：

This is my test version for a custom delete function:

public function deleteFile($path){
    set_error_handler(function($errLevel, $errString){
        debug($errLevel);
        debug($errString);
    });
    unlink($path);
    restore_error_handler();
}

对于 $ errLevel 和 $ errString 我得到 2 （E_WARNING）和取消链接（/ tmp / fooNonExisting）：没有这样的文件或目录

For $errLevel and $errString I get 2 (E_WARNING) and unlink(/tmp/fooNonExisting): No such file or directory

一个相当大胆的方法就是这样：

A rather bold approach would be like this:

if( strpos($errString, 'No such file or directory') !== false ) {
    throw new FileNotFoundException();
};

问题1：我可以依赖于不同PHP版本的错误字符串相同吗？问题2：有更好的方法吗？

Question 1: How much can I rely on the error string being the same across different PHP versions? Question 2: Is there a much better way?

推荐答案

我将简化代码：

public function deleteFile($path){

    if (!file_exists($path) {
        throw new FileNotFoundException();
    }else{
        unlink($path);
    }

    if (file_exists($path) {
        throw new FileNotDeleted();
    }
}

然后你没有抓住 $ errstr 并执行复杂的错误捕获，当引入异常时，它将适用于PHP 4。

Then you don't have to catch the $errstr and do complicated error catching. And it will work down to PHP 4 when exceptions were introduced.

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