如何从Python中的异常对象获取堆栈跟踪？ [英] How do I get the stack trace from an Exception Object in Python?

问题描述

如何从Exception对象本身获取完整的堆栈跟踪？

How can I get the full stack trace from the Exception object itself?

考虑以下代码作为问题的简化示例：

Consider the following code as reduced example of the problem:

last_exception = None
try:
    raise Exception('foo failed')
except Exception as e:
    last_exception = e
# this happens somewhere else, decoupled from the original raise
print_exception_stack_trace(last_exception)

推荐答案

编辑：我撒谎，对不起。 e .__ traceback __ 是你想要的。

I lied, sorry. e.__traceback__ is what you want.

try:
    raise ValueError
except ValueError as e:
    print( e.__traceback__ )

>c:/python31/pythonw -u "test.py"
<traceback object at 0x00C964B8>
>Exit code: 0

这是仅在Python 3中有效;您不能在早期版本中执行此操作。

This is only valid in Python 3; you can't do it in earlier versions.

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