Python try / except：显示我的变量后出现错误的原因 [英] Python try/except: Showing the cause of the error after displaying my variables

问题描述

我不确定正确的话要搜索什么。我想在一个except块中显示错误对象的部分（类似于VBScript中的err对象，它具有Err.Number和Err.Description）。例如，我想显示我的变量的值，然后显示确切的错误。显然，我在下面引起了一个除零的错误，但是我怎么能打印出这个事实？

  try：
x = 0 
y = 1 
z = y / x 
z = z + 1 
 printz =％d％（z）
除了：
 print异常值：x =％dy =％d％（x，y）
 print错误在线...
 print错误的原因是...
  

解决方案

  try：
 1/0 
除了例外为e：
打印e 
  

I'm not even sure what the right words are to search for. I want to display parts of the error object in an except block (similar to the err object in VBScript, which has Err.Number and Err.Description). For example, I want to show the values of my variables, then show the exact error. Clearly, I am causing a divided-by-zero error below, but how can I print that fact?

try: 
    x = 0 
    y = 1 
    z = y / x 
    z = z + 1 
    print "z=%d" % (z) 
except: 
    print "Values at Exception: x=%d y=%d " % (x,y) 
    print "The error was on line ..." 
    print "The reason for the error was ..." 

解决方案

try:  
    1 / 0 
except Exception as e: 
    print e

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