如何排序列表按字节顺序为AWS-电话 [英] How to sort a list by byte-order for AWS-Calls

问题描述

在看看的http：//联营公司 - 亚马逊。 s3.amazonaws.com/signed-requests/helper/index.html

下面的名称 - 值对：

 服务= AWSECommerceService
版本= 2011-08-01
AssociateTag = Put​​YourAssociateTagHere
操作= ItemSearch
SearchIndex =图书
关键词=哈利·波特+
时间戳= 2015-09-26T14：10：56.000Z
AWSAccessKeyId = 123
 

  

的名称 - 值对已按字节顺序进行排序

应导致

  AWSAccessKeyId = 123
AssociateTag = Put​​YourAssociateTagHere
关键词=哈里％20potter
操作= ItemSearch
SearchIndex =图书
服务= AWSECommerceService
时间戳= 2015-09-26T14％3A10％3A56.000Z
版本= 2011-08-01
 

如何实现这一目标在研发？

据我可以告诉他们被排序的 as.numeric（charToRaw（名称））值。如果第一个值等于然后它们通过第二个分选，然后在第三等

问：如何做到这一点在研发

解决方案

 ＃名称 - 值对
NVP＆LT;  - 列表（
服务=AWSECommerceService
版本=2011-08-01，
AssociateTag=PutYourAssociateTagHere，
运行=ItemSearch
SearchIndex=书，
关键词=哈利·波特，
时间戳=2015-09-26T14：10：56.000Z
AWSAccessKeyId=123
）
 

获取字节：

 字节＆LT;  - 功能（CHR）{
  as.data.frame（T（as.numeric（charToRaw（CHR））））
}
 

字节计算，和rbind值

  B＆LT;  -  lapply（名称（NVP），字节）
B＆LT;  -  data.table :: rbindlist（B，补= TRUE）＃比基地等:: rbind，这填补了NA
 

ORDER BY第一列的名称，然后通过第二，第三方，...等等

 名称（NVP）[do.call（订单，as.list（B））]

[1]AWSAccessKeyIdAssociateTag，关键词操作SearchIndex
[6]服务时间戳，版本
 

所以最后 NVP [do.call（订单，as.list（B））] 的正确排序列表返回

Having a look at http://associates-amazon.s3.amazonaws.com/signed-requests/helper/index.html

The following Name-Value Pairs:

Service=AWSECommerceService
Version=2011-08-01
AssociateTag=PutYourAssociateTagHere
Operation=ItemSearch
SearchIndex=Books
Keywords=harry+potter
Timestamp=2015-09-26T14:10:56.000Z
AWSAccessKeyId=123

The name-value pairs have been sorted according to byte-order

Should result in

AWSAccessKeyId=123
AssociateTag=PutYourAssociateTagHere
Keywords=harry%20potter
Operation=ItemSearch
SearchIndex=Books
Service=AWSECommerceService
Timestamp=2015-09-26T14%3A10%3A56.000Z
Version=2011-08-01

How to achieve this in R?

As far as i can tell they are sorted by their as.numeric(charToRaw(name)) values. If the first value is equal then they are sorted by the second one, then the third and so on.

Question: How to do this in R?

解决方案

# Name-Value-Pairs
nvp <- list(                                
"Service"="AWSECommerceService",
"Version"="2011-08-01",
"AssociateTag"="PutYourAssociateTagHere",
"Operation"="ItemSearch",
"SearchIndex"="Books",
"Keywords"="harry potter",
"Timestamp"="2015-09-26T14:10:56.000Z",
"AWSAccessKeyId"="123"
)

Get Bytes:

bytes <- function(chr){
  as.data.frame(t(as.numeric(charToRaw(chr))))
}

Calculate Bytes, and rbind the values

b <- lapply(names(nvp), bytes)
b <- data.table::rbindlist(b, fill=TRUE) # other than base::rbind, this fills by NA

Order the names by first column, then by second, by third, ... and so on

names(nvp)[do.call(order, as.list(b))]

[1] "AWSAccessKeyId" "AssociateTag"   "Keywords"       "Operation"      "SearchIndex"   
[6] "Service"        "Timestamp"      "Version"   

So finally nvp[do.call(order, as.list(b))] returns in the properly sorted list

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