当父点击时检查树的子节点[ExtJS] [英] check child nodes of a tree when a parent is clicked [ExtJS]

问题描述

我想知道如何在ExtJs中点击一个特定的节点来检查一棵树的兄弟节点。

我给每个节点添加了id，我可以访问点击的节点的ID。那么我该如何继续自动检查子节点？

有人请帮助我..

解决方案

  //或任何其他方式在您要使用的节点上获取
 var node = treePanel.getNodeById（'your-id ）; 
 node.eachChild（function（n）{
 n.getUI（）。toggleCheck（true）; 
}）; 
  

如果你想让这个工作在当前节点的整个子树上，你必须做一些递归。

更多集成：

  treePanel.on （'checkchange'，function（node，checked）{
 node.eachChild（function（n）{
 n.getUI（）。toggleCheck（checked）; 
}）; 
}）; 
  

I would like to know how can i check the sibling nodes of a tree while clicking on a particular node in ExtJs.

I had given id's for each node and i can access the id of a clicked node. then how can i proceed to checking the child nodes automatically ??

somebody please help me..

解决方案

// or any other way of getting hands on the node you want to work with
var node = treePanel.getNodeById('your-id');
node.eachChild(function(n) {
    n.getUI().toggleCheck(true);
});

If you want this to work on the whole subtree of the current node, you'll have to do some recursion.

A little more integrated:

treePanel.on('checkchange', function(node, checked) {
    node.eachChild(function(n) {
        n.getUI().toggleCheck(checked);
    });
});

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