调用线程必须是STA，因为许多UI组件需要这样做 [英] The calling thread must be STA, because many UI components require this

问题描述

我正在使用 http：//www.codeproject .com / KB / IP / Facebook_API.aspx

我试图调用 WPF 创建的wiki / Extensible_Application_Markup_Languagerel =noreferrer> XAML 。但是它给我一个错误：

调用线程必须是STA，因为许多UI组件需要这个。

我不知道该怎么办我试图这样做：

  FacebookApplication.FacebookFriendsList ffl = new FacebookFriendsList（）; 
  

但它是给我的错误。

我添加了一个后台工作者：

  static BackgroundWorker bw = new BackgroundWorker（）; 
 
 static void Main（string [] args）
 {
 bw.DoWork + = bw_DoWork; 
 bw.RunWorkerAsync（Message to worker）; 
 Console.ReadLine（）; 
} 
 
 static void bw_DoWork（object sender，DoWorkEventArgs e）
 {
 //这是在工作线程上调用
 FacebookApplication.FacebookFriendsList ffl =新的FacebookFriendsList（）; 
 
 Console.WriteLine（e.Argument）; //将Message to worker写入
 
 //执行耗时的任务... 
} 
  

解决方案

如果从主线程进行调用，则必须将STAThread属性添加到Main方法中，如上一个答案所述。 p>

如果您使用单独的线程，则需要在STA（单线程公寓）中，后台工作线程不是这样。您必须自己创建线程，如下所示：

  Thread t = new Thread（ThreadProc） ; 
 t.SetApartmentState（ApartmentState.STA）; 
 
 t.Start（）; 
  

ThreadProc是ThreadStart类型的代理。

I am using http://www.codeproject.com/KB/IP/Facebook_API.aspx

I am trying to call the XAML which is created using WPF. But it gives me an error:

The calling thread must be STA, because many UI components require this.

I don't know what to do. I am trying to do this:

FacebookApplication.FacebookFriendsList ffl = new FacebookFriendsList();

But it is giving me that error.

I added a background worker:

static BackgroundWorker bw = new BackgroundWorker();

static void Main(string[] args)
{
    bw.DoWork += bw_DoWork;
    bw.RunWorkerAsync("Message to worker");
    Console.ReadLine();
}

static void bw_DoWork(object sender, DoWorkEventArgs e)
{
    // This is called on the worker thread
    FacebookApplication.FacebookFriendsList ffl = new FacebookFriendsList();

    Console.WriteLine(e.Argument);        // Writes "Message to worker"

    // Perform time-consuming task...
}

解决方案

If you make the call from the main thread, you must add the STAThread attribute to the Main method, as stated in the previous answer.

If you use a separate thread, it needs to be in a STA (single-threaded apartment), which is not the case for background worker threads. You have to create the thread yourself, like this:

Thread t = new Thread(ThreadProc);
t.SetApartmentState(ApartmentState.STA);

t.Start();

with ThreadProc being a delegate of type ThreadStart.

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