Facebook C＃SDK：遍历JsonArray获取跟踪数据的价值 [英] Facebook C# SDK: Traverse The JsonArray To Get The Value of Tracking Data

问题描述

这是一个跟进：

(OAuthException) (#15) The method you are calling must be called with an app secret signed session

相当于file_get_contents（PHP）的C＃ / a>

C# equivalent of file_get_contents (PHP)

Facebook API：我可以邀请一个测试用户到我的应用程序吗？

所以我现在是最后一步。邀请用户接受邀请后，我设法邀请用户并获取请求信息。现在我需要遍历结果对象（JsonArray），并获取数据字段的值，该字段是使用请求对话

So I'm at the final step now. I managed to invite users and get the request info once the invited user accepts the invitation. Now I need to traverse the result object (JsonArray) and get the value of the data field which is the tracking data that is sent with the Request Dialog

我尝试使用点语法来遍历对象和其他一些东西，得到它所以这里是我的代码（不起作用）：

I've tried using dot syntax to traverse the object and some other things but I couldn't get it. So here's my code (which doesn't work):

        dynamic requestInfo = fb.Get("/me/apprequests/");
        if (requestInfo.data.Count > 0)
        {
            //var c = requestInfo.data.data;
            var a = requestInfo[0]["data"];
            ViewData.Add("TrackingData", "the value");
        }

结果如下：

{data：[{id：1001200425907，application：{name：MyFirstTestApp，id：193005690721590} ：{name：Margaret
Diibjcfhg

{"data":[{"id":"1001200425907","application":{"name":"MyFirstTestApp","id":"193005690721590"},"to":{"name":"Margaret Diibjcfhg

Sadansteinskymanbergwitz，id：499203687}，from：{name Nancy
Diibjcfhf

Sadansteinskymanbergwitz","id":"499203687"},"from":{"name":"Nancy Diibjcfhf

Changwitz，id：499203686}，data：someCode，message：
$ b应用程序！，created_time：2011-05 -

Changwitz","id":"499203686"},"data":"someCode","message":"Invitation to the test application!","created_time":"2011-05-

18T09：31：40 + 0000}]}

18T09:31:40+0000"}]}

推荐答案

您正在查找的数据在 requestInfo [data ] [0] [data] 我使用Firefox的JSONView插件来帮助我遍历结构来给出答案，我建议它帮助你在将来找出这样的东西。

The data you are looking for is in requestInfo["data"][0]["data"] I used the JSONView addon for Firefox to help me traverse the structure to give you the answer, and I recommend it to help you figure out stuff like this in the future.

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