如何在Java中解析或分割URL地址？ [英] How to parse or split URL Address in Java?

问题描述

https://graph.facebook.com/me/home?limit=25&since=1374196005

我可以得到（或拆分）参数（避免硬编码）？

像这样

https /// graph.facebook.com /// 我/ home /// {limit = 25，sincse = 1374196005}

解决方案

使用Android的 Uri 类。 http://developer.android.com/reference/android/net/Uri.html

  Uri uri = Uri.parse（https://graph.facebook.com/me/home?limit=25&since = 1374196005\" ）; 
 String protocol = uri.getScheme（）; 
 String server = uri.getAuthority（）; 
 String path = uri.getPath（）; 
设置< String> args = uri.getQueryParameterNames（）; 
 String limit = uri.getQueryParameter（limit）; 
  

If I have url address.

https://graph.facebook.com/me/home?limit=25&since=1374196005

Can I get(or split) parameters (avoiding hard coding)?

Like this

https /// graph.facebook.com /// me/home /// {limit=25, sincse=1374196005}

解决方案

Use Android's Uri class. http://developer.android.com/reference/android/net/Uri.html

Uri uri = Uri.parse("https://graph.facebook.com/me/home?limit=25&since=1374196005");
String protocol = uri.getScheme();
String server = uri.getAuthority();
String path = uri.getPath();
Set<String> args = uri.getQueryParameterNames();
String limit = uri.getQueryParameter("limit");

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