在C中打开FIFO时遇到问题 [英] Having a trouble with opening FIFO in C

问题描述

我在C中打开FIFO时遇到了麻烦。首先我用mkfifo（）函数创建了它们，权限为0777，当我试图打开它们时，它成功地打开了第一个FIFO，然后进程将停留在打开第二个FIFO，这是我的代码：

$ $ $ $ $ c $ fd1 = open（FIFO1_PATH，O_WRONLY）;
fd2 = open（FIFO2_PATH，O_WRONLY）;

这不会被执行，但是一旦我注释了第二行，它就会执行！每个流程的开放FIFO数量是否有限制？我不知道为什么会发生这种情况..我只花了3小时试图找出问题是什么，但没有任何结果：（$ / b $ b

解决方案为了回答你关于限制的问题 - 在Linux中，默认情况下是一个进程的1024个文件描述符，你的问题可能不是打开第二个FIFO来读取写入数据块。

I'm having a trouble in opening FIFOs in C.. first I created them using mkfifo() function with permission : 0777, and when I tried to open them, it succeeded in opening the first FIFO only, then the process will stuck in opening the second FIFO, and this is my code :

fd1 = open("FIFO1_PATH", O_WRONLY );
fd2 = open("FIFO2_PATH", O_WRONLY );

This will not be executed, but once I comment the second line, it executes ! Is there a limit for the number of opening FIFOs per process ? I don't know why is this happening.. I just spent 3 Hours trying to figure out what the problem is, but without any results :(

解决方案

To answer you question about limits - default in Linux is 1024 file descriptors for a process. Your problem is probably not opening the second FIFO for reading so open for writing blocks.

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