在Python中将unicode写入二进制文件 [英] writing unicode to binary file in python

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本文介绍了在Python中将unicode写入二进制文件的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我想知道如何将Unicode(utf-8)写入二进制文件。这里是背景:我有一个40字节的头(10个整数),和一个可变数量的三个int结构的表。写这些是蛋糕。

现在,我想添加一堆字符串到文件的末尾。

编写常规的基于ASCII的字符串很简单:

  value =( 'ab')
s = struct.Struct('2s')
packed_data = s.pack(value)

我学习了如何从将字符串解释为打包的二进制数据



但是,有没有办法做到基于unicode(utf-8)的字符串?

?有没有人做过这个? Unicode!= UTF-8。 UTF-8是Unicode的二进制编码,所以只需要像编写ASCII字符串那样编写UTF-8字符串即可。不需要打包编码的字符串。
$ b

 #编码:utf8 
导入结构
text = u'我是美国人。'
encoded_text = text.encode('utf8')

#证明包装是多余的...
format ='{0} s' .format(len(encoded_text))
packed_text = struct.pack(format,encoded_text)
print encoded_text == packed_text#result:True

因此,只需要编码你的Unicode字符串,并在写入你的打包整数后将它们追加到文件中。

I'm wondering how to write unicode (utf-8) to a binary file. Here's the background: I've got a 40 byte header (10 ints), and a table with a variable number of triple-int structs. Writing these was cake.

Now, I want to add a bunch of strings to the end of the file.

Writing regular ASCII based strings is easy:

value = ('ab')
s = struct.Struct('2s')
packed_data = s.pack(value)

I learned how to do this from the Interpret strings as packed binary data.

But is there a way to do this for unicode (utf-8) based strings?

Any ideas? Has anyone done this before?

解决方案

Unicode != UTF-8. UTF-8 is a binary encoding of Unicode, so just write the UTF-8 string just as you would an ASCII string. No need to pack an encoded string either. It's already "just a bunch of bytes".

# coding: utf8
import struct
text = u'我是美国人。'
encoded_text = text.encode('utf8')

# proof packing is redundant...
format = '{0}s'.format(len(encoded_text))
packed_text = struct.pack(format,encoded_text)
print encoded_text == packed_text # result: True

So just encode your Unicode strings and append them to the file after writing your packed ints.

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