播放框架CRUD文件上传 [英] Play framework CRUD file upload

问题描述

有谁知道添加文件上传到Play的CRUD表单的方法？到目前为止，我有一个像这样的部分：

 ＃{form action：@save（object._key（）），enctype ：'multipart / form-data'} 
＃{crud.form} 
＃{crud.custom'file'} 
< label for =uploadFile> 
文件
< / label> 
< input type =fileid =uploadFilename =uploadFile/> 
＃{/ crud.custom} 
＃{/ crud.form} 
< p class =crudButtons> 
< input type =submitname =_ savevalue =& {'crud.save'，type.modelName}/> 
< input type =submitname =_ saveAndContinuevalue =& {'crud.saveAndContinue'，type.modelName}/> 
< / p> 
＃{/ form} 
  

但是我不知道如何编写控制器方法处理上传。
我不想将文件存储在数据库中作为一个blob，我不想在文件系统上。

解决方案

这段代码会将您的文件保存到项目的data / attachments目录中：

模型

 包模型; 
 
 import play.db.jpa.Blob; 
 import play.db.jpa.Model; 
 
 import javax.persistence.Entity; 
 
 @Entity 
 public class MyApp extends Model {
 
 public String name; 
公共Blob文件; 
 
 $ b  

模板

 ＃{form action：@create（），enctype：'multipart / form-data'} 
＃{crud.form /} 
 
< label for =uploadFile>文件< / label> 
< input type =fileid =uploadFilename =myapp.file/> 
 
< p class =crudButtons> 
< input type =submitname =_ save
 value =& {'crud.save'，type.modelName}/> 
< input type =submitname =_ saveAndContinue
 value =& {'crud.saveAndContinue'，type.modelName}/> 
< / p> 
 $ {/ form} 
  

控制器

 程序包控制器
 
 import play。*; 
 import play.mvc。*; 
 
 import java.util。*; 
 
导入模型。*; 
 
 / *从CRUD模块扩展
 *控制器的自定义控制器。 
 * / 
 public class MyController extends CRUD {
 
 // ... 
 
 //将保存对象
 public static void创建（MyApp对象）{
 
 / *获取当前类型的控制器并在非空* / 
上进行测试ObjectType type = ObjectType.get（getControllerClass（））; 
 notFoundIfNull（type）; 
 
 / *我们执行生成的crud模块表单域验证* / 
 validation.valid（object）; 
 if（validation.hasErrors（））{
 renderArgs.put（error，Messages.get（crud.hasErrors））; 
尝试{
 render（request.controller.replace（。，/）+/blank.html，type，object）; 
 catch（TemplateNotFoundException e）{
 render（CRUD / blank.html，type，object）; 
 
 
 $ b $ *将我们的对象保存到db * / 
 object._save（）; 
 $ b $ *显示消息* / 
 flash.success（Messages.get（crud.created，type.modelName））; 
 if（params.get（_ save）！= null）{
 redirect（request.controller +.list）; 
 
 if（params.get（_ saveAndAddAnother）！= null）{
 redirect（request.controller +.blank）; 
 
 
 
 
 
 
 $ b $ p如上所述，通过自己的领域克服形式和压倒crud方法创造。同样可以做更新记录。 
您可以在application.conf中更改data / attachments目录：
 $ b $ h2 application.conf 
 
 
 ＃... 
＃存放Blob内容的路径
 attachments.path = data / attachments 
＃... 
  code> 
有关更多详细信息，请参阅 http://www.lunatech-research.com/playframework-file-upload-blob  
 
anyone know a way to add a file upload to Play's CRUD form? So far I have a view part like this:
   #{form action:@save(object._key()), enctype:'multipart/form-data'}
    #{crud.form}
        #{crud.custom 'file'}
            <label for="uploadFile">
                File
            </label>
            <input type="file" id="uploadFile" name="uploadFile" />
        #{/crud.custom}
    #{/crud.form}
    <p class="crudButtons">
        <input type="submit" name="_save" value="&{'crud.save', type.modelName}" />
        <input type="submit" name="_saveAndContinue" value="&{'crud.saveAndContinue', type.modelName}" />
    </p>
#{/form}
But I don't know how to write the controller method to handle the upload.
And I don't want to store the file in the db as a blob, I wan't it on filesystem. 
解决方案
This code will save your file into a "data/attachments" directory of your project:

Model

package models;

import play.db.jpa.Blob;
import play.db.jpa.Model;

import javax.persistence.Entity;

@Entity
public class MyApp extends Model {

   public String name;
   public Blob file;

}


Template

#{form action:@create(), enctype:'multipart/form-data'}
    #{crud.form /}

    <label for="uploadFile">File</label>
    <input type="file" id="uploadFile" name="myapp.file" />

    <p class="crudButtons">
        <input type="submit" name="_save"
            value="&{'crud.save', type.modelName}" />
        <input type="submit" name="_saveAndContinue"
            value="&{'crud.saveAndContinue', type.modelName}" />
    </p>
#{/form}


Controller

package controllers

import play.*;
import play.mvc.*;

import java.util.*;

import models.*;

/* Custom controller that extends
 * controller from CRUD module.
 */    
public class MyController extends CRUD {

    // ...

    // Will save your object
    public static void create(MyApp object) {

    /* Get the current type of controller and test it on non-empty */
    ObjectType type = ObjectType.get(getControllerClass());
    notFoundIfNull(type);

    /* We perform validation of the generated crud module form fields */
    validation.valid(object);
    if (validation.hasErrors()) {
        renderArgs.put("error", Messages.get("crud.hasErrors"));
        try {
            render(request.controller.replace(".", "/") + "/blank.html", type, object);
        } catch (TemplateNotFoundException e) {
            render("CRUD/blank.html", type, object);
        }
    }

    /* Save our object into db */
    object._save();

    /* Show messages */
    flash.success(Messages.get("crud.created", type.modelName));
    if (params.get("_save") != null) {
        redirect(request.controller + ".list");
    }
    if (params.get("_saveAndAddAnother") != null) {
        redirect(request.controller + ".blank");
    }

}
As stated above, you simply complements crud form by your own field and overrides crud method "create". The same can be done to update the record.
You can change "data/attachments" directory in your application.conf:

application.conf

# ...
# Store path for Blob content
attachments.path=data/attachments
# ...
For more details see http://www.lunatech-research.com/playframework-file-upload-blob

                        
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