weka stringToWordVector过滤stringOptions [英] weka stringToWordVector filter stringOptions

问题描述

我试图用weka的java API过滤数据集。我已经用Weka的GUI成功地过滤了我想用stringToWordVector过滤器的属性，但是我似乎无法在我的java代码中做同样的事情。我复制并粘贴了自动生成的过滤参数，并将它们发布到我的代码中，但仍然继续出现错误。目前，我的代码如下所示：

 实例newInsts = new Instances（this.instances）; 
 StringToWordVector stringFilter = new StringToWordVector（）; 
 stringFilter.setOptions（
 weka.core.Utils.splitOptions（ -  R 1,2,3,4,8 -W 1000 
 -prune-rate -1.0 -N-0 -stemmer 
 weka.core.stemmers.NullStemmer -M 1 
 -tokenizer \weka.core.tokenizers.WordTokenizer 
 -delimiters \\\r\\\ \\\t;：\\\'\\\ （）？\））; 
 stringFilter.setInputFormat（newInsts）; 
 newInsts = Filter.useFilter（newInsts，stringFilter）; 
  

但是我一直在我的eclipse控制台中发现这个错误：没有赋予-delimiters选项的值。

（我在上面的代码中增加了额外的可读性空间，我猜这和转义字符/引号有关系。）

谢谢！

解决方案

实际上可以省略大部分选项，因为它们是StringToWordVector的默认值。您要传递的分隔符是默认分词器中的默认分隔符， WordTokenizer ，它们是：

 '\r\\\
\t。，;：' （）？！'
  

I'm trying to filter a dataset using weka's java API. I've successfully filtered the attributes I want with a stringToWordVector filter in Weka's GUI but I can't seem to do the same in my java code. I copied and pasted the auto-generated filtering parameters and posted them into my code but am continuing to get errors. Currently, my code looks like this:

Instances newInsts = new Instances(this.instances);
StringToWordVector stringFilter = new StringToWordVector();
stringFilter.setOptions(
            weka.core.Utils.splitOptions("-R 1,2,3,4,8 -W 1000 
                                          -prune-rate -1.0 -N 0 -stemmer
                                           weka.core.stemmers.NullStemmer -M 1
                                          -tokenizer \"weka.core.tokenizers.WordTokenizer 
                                          -delimiters \" \\r\\n\\t.,;:\\\'\\\"()?!\""));
stringFilter.setInputFormat(newInsts);
newInsts = Filter.useFilter(newInsts, stringFilter);

But I keep getting this error in my eclipse console: No value given for -delimiters option.

(I added extra spacing for readability in the above code. I suspect this has something to do with escaping characters/quotations marks...)

Thanks!

解决方案

You can actually omit most of the options, as they are the defaults for StringToWordVector. The delimiters you're trying to pass are the default delimiters in the default tokenizer, WordTokenizer, which are:

' \r\n\t.,;:'"()?!'

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