用Javascript移动一个对象（元素） [英] Move an object (element) one step up with Javascript

问题描述

我有几个这样的对象：

我想移动类型和值一步，所以它们将在字段旁边，然后删除 data 。

当 departments 转换为JSON时，它看起来像这样：

  
 {field：DEPARTMAN_NO，
data：{type：numeric，comparison：eq，value：11} 
} ，
 {field：DEPARTMAN_ADI，
data：{type：string，value：bir} 
} 
] 
  

我试过了：

  departments = grid.filters.getFilterData（）; 
 i = {}; 
 for（var i in department）{
 department = i.data; 
 delete.department.data; 
}; 
  

但是没有用。

解决方案

1）首先，循环部门，我们称之为 department ;

2）您想将 department.data 的属性移动到 department ，From另一个角度，可以将 department 的属性移动到 department.data 并返回 department。数据，代码如下：

pre $ var $ DEPARTMAN_NO，
data：{
type：numeric，
comparison：eq，
value：11
}
字段：DEPARTMAN_ADI，
data：{
type：string，
value：bir
}
}]，
部门;

for（var i = 0，len = departments.length; i< len; i ++）{
department = departments [i]; （部门中的var键）{
if（key！=='data'&&department.data）{
department.data [key] = department [键];
}
}
部门[i] = department.data ||部; //如果没有department.data，没有改变
}

console.log（departments）;

结果：

查看完整的演示 http://jsfiddle.net/KVYE5/

I have several objects like this:

I want to move type and value one step up so they will be next to field, and then delete data.
It looks like this when departments is converted to JSON:

[
    {"field"    : "DEPARTMAN_NO",
     "data"     : { "type":"numeric" , "comparison":"eq" , "value":11 }
    },
    {"field"    : "DEPARTMAN_ADI",
     "data"     : { "type":"string" , "value":"bir" }
    }
]

I have tried:

departments = grid.filters.getFilterData();
i = {};
for(var i in department) {
department = i.data;
delete.department.data;
};

but it dosen't work.

解决方案

1) First, loop departments, each item we call it department;
2) You want to move department.data's properties to department, From another angle, you can move department's properties to department.data and return department.data, code like:

var departments = [{
        "field": "DEPARTMAN_NO",
        "data": {
            "type": "numeric",
            "comparison": "eq",
            "value": 11
        }
    }, {
        "field": "DEPARTMAN_ADI",
        "data": {
            "type": "string",
            "value": "bir"
        }
    }],
    department;

for (var i = 0, len = departments.length; i < len; i++) {
    department = departments[i]; // department
    for (var key in department) {
        if (key !== 'data' && department.data) {
            department.data[key] = department[key];
        }
    }
    departments[i] = department.data || department; // if no department.data, no change
}

console.log(departments);

result:

view the full demo http://jsfiddle.net/KVYE5/

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