从过滤器接收只有一个数据结构 [英] Receive only one data from filters to struct
问题描述
struct SalasMaster {
让id:Int
让nombre:String
let latitud:String
let longitudinal:String
let piso:String
let observaciones:String
let pabellon :字符串
}
var Salas = [SalasMaster]()
...接收数据...
... dump(Salas)
例子 - >
- 纬度:-29.96429300
- longitudinal:-71.34937300
- piso: 1
- observaciones:
- pabellon:X - Escuela deIngeniería
最后,我想要过滤的示例id,在这一刻我得到一个数组在那里,以及所有其他相应的数据
<$ p $ ...
var arrayFiltered = Salas.filter {$ 0.id == 307}
打印(arrayFiltered) - > [SalasMaster(id:307,注:SALA DE PROYECTOS,纬度:-29.96429300,纵向:-71.34937300,piso:1,观察员:,pabellon:X - Escuela deIngeniería) ]
但我找不到方法只返回一个我感兴趣的数据从ID,在这种情况下,我只想捕获纬度,但在另一种情况下,我可能需要另一个。
您可以使用 first(where:)
,因为它会给你第一个匹配的记录并停止搜索。
if let sale = Salas.first(where:{$ 0.id == 307}){
print(sale.latitud)
}
Short question, I have the following structure, which I store in "Salas"
struct SalasMaster {
let id: Int
let nombre: String
let latitud: String
let longitud: String
let piso: String
let observaciones: String
let pabellon: String
}
var Salas = [SalasMaster]()
...receiving data...
...dump(Salas)
example -> SalasMaster
- id: 307
- nombre: "SALA DE PROYECTOS "
- latitud: "-29.96429300"
- longitud: "-71.34937300"
- piso: "1"
- observaciones: ""
- pabellon: "X - Escuela de Ingeniería"
And finally what I want is to filter the example id, at this moment I get an array where it is, along with all other corresponding data
...filter data...
var arrayFiltered = Salas.filter{$0.id == 307}
Print(arrayFiltered) -> [SalasMaster(id: 307, nombre: "SALA DE PROYECTOS ", latitud: "-29.96429300", longitud: "-71.34937300", piso: "1", observaciones: "", pabellon: "X - Escuela de Ingeniería")]
But I can't find the way to return only one data that I'm interested in retrieving from "id", in this case I want to capture only "latitud", although in another case I might need another one.
You can use first(where:)
for that because it will give you first matching record and stop searching after it.
if let sale = Salas.first(where: { $0.id == 307 }) {
print(sale.latitud)
}
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