在函数内返回0到n个数组值 [英] Return 0 to n arrays values inside a function

问题描述

我有一个非常复杂的问题。

我有这个动态数组，可能包含0到 - > n个值：

这是一个例子：

  var array = [2,3,8]; 
  

这是第二个例子：

  var array = [2,3,8,15,25]; 
  

现在，我需要执行这个函数（由stakoverflower给出），但是我不知道如何每次考虑每个值;这是一个静态函数，现在，这是行之有效的：

$ $ $ $ $ $ $ c $ var filterList $ filter（'filter'）（$ scope .footballers，function（i）{
return（i.identifiant === 2 || i.identifiant === 3 || i.identifiant === 8）;
}）;

但是看起来，它适用于第一个数组示例，但不适用于第二个数组示例。如果我想对待第二个数组，我需要输入：

 <$ c 
 
 
 c> var filteredList = $ filter（'filter'）（$ scope.footballers，function（i）{
 return（i.identifiant === 2 || i.identifiant === 3 || i.identifiant === 8 || i.identifiant === 15 || i.identifiant === 25）; 
}）; 
  

我的问题是：如何在$ filter函数中添加for循环，对待第二个数组或任何长的数组？

如果你有一个想法，非常感谢你。然后循环会自动输入i.identifiant === array [0]，i.identifiant === array [1]等等！

我从来没有在这种情况下，我真的不知道如何返回一个动态的长数组！

这也适用于第一个例子：

  var filteredList = $ filter（'filter'）（$ scope.footballers，function（i）{
 return（i.identifiant === array [0] || i.identifiant === array [1] || i.identifiant === array [2]）; 
}）; 
  

但是我怎么能如果我的数组包含12个值？我需要一个循环，但我不知道该怎么做！

然后循环会输入i.identifiant === array [x]

哎呀，我忘记了，我的目标是显示一个足球运动员名单列表中的阵列阵列内使用angularjs。进入拖放应用程序。这就是为什么我过滤，$ scope.footballers内有大量的标识符，但我只想保留一些，这些在阵列内呈现！问题是数组数组可能包含2个值以及25个值。

我正在考虑一个内部或末尾的eval（）循环

解决方案

好的JB Nizet给了我答案，非常感谢，它超过了我的水平，但它工作，所以好的！

如果你对我的实验室感到好奇，那就在这里：

http://nicolash.org/football/#/liste

有一个愉快的一天

解决与此相反的问题：

$ b $是可能过滤角度js的由包含另一个数组b

最后得到了这个反函数：
$ b $ $ $ $ $ $ $ $ $ $ $ $ scope $ footer $ filter $' ）（$ scope.footballers，函数（i）{
return presence_ equipe.indexOf（i.identifiant）=== -1
}）;

非常感谢！

I've got a really complex problem.

I've got this dynamic array , that might include 0 to -> n values :

This is an example :

var array =[2,3,8];

this is the second example :

var array =[2,3,8,15,25];

Now, i need to execute this function( gently given by a stakoverflower), but i don't know how to consider each values each times; it is a static function for now, that is working well :

var filteredList = $filter('filter')($scope.footballers, function (i) {
      return (i.identifiant === 2 || i.identifiant === 3 || i.identifiant === 8);
 });

But look, it works for the first array example, but not for the second array example.

If i want to treat the second array, i need to type this :

 var filteredList = $filter('filter')($scope.footballers, function (i) {
      return (i.identifiant === 2 || i.identifiant === 3 || i.identifiant === 8 || i.identifiant === 15 || i.identifiant === 25);
 });

My question is : How could i add a for loop inside the $filter function, to be able to treat the second array or whatever long the array is ?

Thank you a lot if you have an idea. The loop would then automatically type i.identifiant === array[0], i.identifiant === array[1] and so on !

I've never encoutered this case, and i really don't know how to return a dynamic long array !

This would also work for the first example :

    var filteredList = $filter('filter')($scope.footballers, function (i) {
      return (i.identifiant === array[0] || i.identifiant === array[1] || i.identifiant === array[2]);
 });

But how could i do if my array contains 12 values ??? I need a loop, but i dont know how to do at all !

The loop would then be supposed to type "i.identifiant === array[x]"

Ooops , i forgot, my goal is to display a list of footballers whoses identifiers are presents inside the array "array", using angularjs. Into a drag and drop application. That is why i filter, there are a large amount of identifiers inside $scope.footballers, but i only wanna keep a few, the ones presents inside the array ! The problem is that the array "array" may contain 2 values as well as 25 values .

I was thinking about a loop with an eval() inside or at the end?

解决方案

Ok JB Nizet gave me the answer, thank you a lot, it's above my level, but it is working, so nice !.

If u're curious about my labo, it's here :

http://nicolash.org/football/#/liste

have a nice day

Solved the inverse problem with this : Is it possible to filter angular.js by containment in another array?

And finally got that inverse function :

$scope.footballers = $filter('filter')($scope.footballers, function (i) {
       return presence_equipe.indexOf(i.identifiant) === -1
});

thanks a lot !!

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