使用find命令但排除两个目录中的文件 [英] Use find command but exclude files in two directories

问题描述

我想查找以 _peaks.bed 结尾的文件，但排除 tmp 和 scripts 文件夹。

我的命令是这样的：

  find。 -type**！-name* scripts *\）
  

但是没有奏效。 tmp 和脚本文件夹中的文件仍然会显示。

/ code>：

  find。 -type f -name* _peaks.bed！ -path./tmp/*！ -path./scripts/*
  

解释：

• find。 - 从当前工作目录开始查找（默认为递归）


• -type f - 指定为 find li>
  
• -name* _peaks.bed - 查找名字以 _peaks.bed


• ！ -path./tmp / * - 排除路径以 ./ tmp /


• ！ -path./scripts / * - 同样排除路径以 ./ scripts /

开头的所有结果

测试解决方案：

  $ mkdir abcde 
 $ touch a / 1 b / 2 c / 3 d / 4 e / 5 e / ae / b 
 $ find。型f！ -path./a/*！ -path./b/*
 
 ./d/4 
 ./c/3 
 ./e/a 
 ./e/b 
 ./e/5 
  

您非常接近， - name 选项仅考虑基本名称，其中 -path 考虑整个路径=）

I want to find files that end with _peaks.bed, but exclude files in the tmp and scripts folders.

My command is like this:

 find . -type f \( -name "*_peaks.bed" ! -name "*tmp*" ! -name "*scripts*" \)

But it didn't work. The files in tmp and script folder will still be displayed.

Does anyone have ideas about this?

解决方案

Here's how you can specify that with find:

find . -type f -name "*_peaks.bed" ! -path "./tmp/*" ! -path "./scripts/*"

Explanation:

• find . - Start find from current working directory (recursively by default)
• -type f - Specify to find that you only want files in the results
• -name "*_peaks.bed" - Look for files with the name ending in _peaks.bed
• ! -path "./tmp/*" - Exclude all results whose path starts with ./tmp/
• ! -path "./scripts/*" - Also exclude all results whose path starts with ./scripts/

Testing the Solution:

$ mkdir a b c d e
$ touch a/1 b/2 c/3 d/4 e/5 e/a e/b
$ find . -type f ! -path "./a/*" ! -path "./b/*"

./d/4
./c/3
./e/a
./e/b
./e/5

You were pretty close, the -name option only considers the basename, where as -path considers the entire path =)

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