找到所有的拉链,并解压缩 - Unix [英] Find all zips, and unzip in place - Unix
问题描述
我有一个包含许多文件夹的文件夹,其中一些文件夹中包含zip文件,另一些则不包含。
例如我有:
p> files / A / something.java
files / B / somezipfile.zip
files / C / someotherfile.zip
files / D / AnotherZipFile.zip
我想解压缩它们(假设拉链只包含.java文件),得到如下结果:
files / A / something.java
files / B / javafile.java
$ b files / C / someotherfilefromzip.java
files / D / Anotherfile.java
我不介意ZIP文件是否保留或在解压缩后被删除,或者没有问题。
到目前为止我已经尝试过了。
1)我期望我可以使用管道,我是新来的,就像这样:
find。 -name * .zip |解压缩
这不行。
2)我花了一些时间搜索,最接近我在网上使用的解决方案是:
find。 -name'* .zip'-exec unzip'{}'';'
解压缩把它们解压缩到当前的工作目录中,我想让它们解压到位。我也不明白这个命令,我想我正在努力学习。
任何帮助都非常感谢。
谢谢,
find。 -name'* .zip'-exec sh -c'unzip -d`dirname {}`';'
这个命令在当前目录及其子目录中递归查找名称匹配 *。zip
模式的文件。找到的文件用两个参数执行 sh
命令:
-c
和
unzip -d`dirname< filename>`< filename>
其中< filename>
是找到的文件。命令 sh
是Unix shell解释器。选项 -c
告诉shell下一个参数应该被解释为shell脚本。所以shell解释下面的脚本:
pre $ uncip -d`dirname<
在运行 unzip
shell之前展开命令,通过做各种替代。在这个特定的例子中,它替代了
`dirname< filename>`
pre>
输出命令
dirname< filename>
,它实际上输出放置文件的目录名称。所以,如果文件名是./ a / b / c / d.zip
,shell会像这样擦unzip
:unzip -d ./a/b/c ./a/b/c/d.zip
如果您的ZIP文件名或目录名有空格,请使用以下命令:
find。 -name* .zip-exec sh -c'unzip -d`dirname \{} \`{}'';'
I have been trying for some time and believe I am fairly close to this, but I am fairly new to Unix so have been finding this difficult.
I have a folder, containing many folders, some of which have zip files in them, some which don't. I am trying to unzip all of the zip files in any sub directories in place.
For example I have:
files/A/something.java
files/B/somezipfile.zip
files/C/someotherfile.zip
files/D/AnotherZipFile.zip
I would like to unzip them (assuming the zips contain just .java files), to have a result like: files/A/something.java
files/B/javafile.java
files/C/someotherfilefromzip.java
files/D/Anotherfile.java
I don't mind if the ZIP files remain or are deleted after unzipping, either is fine.
What I have tried so far.
1) I expected I could use piping, which I am new to, like this:
find . -name *.zip | unzip
This doesn't work.
2) I spent some time searching, the closest I got using a solution online is:
find . -name '*.zip' -exec unzip '{}' ';'
This unzips, but unzips them into the current working directory, I wanted them to unzip in place. I also don't understand this command which I would like to as I am trying to learn.
Any help is much appreciated.
Thanks,
解决方案find . -name '*.zip' -exec sh -c 'unzip -d `dirname {}` {}' ';'
This commands looks in current directory and in its subdirectories recursively for files with names matching
*.zip
pattern. For file found it executes commandsh
with two parameters:-c
and
unzip -d `dirname <filename>` <filename>
Where
<filename>
is name of file that was found. Commandsh
is Unix shell interpreter. Option-c
tells shell that next argument should be interpreted as shell script. So shell interprets the following script:unzip -d `dirname <filename>` <filename>
Before running
unzip
shell expands the command, by doing various substitutions. In this particular example it substitutes`dirname <filename>`
with output of command
dirname <filename>
which actually outputs directory name where file is placed. So, if file name is./a/b/c/d.zip
, shell will rubunzip
like this:unzip -d ./a/b/c ./a/b/c/d.zip
In case you ZIP file names or directory names have spaces, use this:
find . -name '*.zip' -exec sh -c 'unzip -d "`dirname \"{}\"`" "{}"' ';'
这篇关于找到所有的拉链,并解压缩 - Unix的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!