如何递归删除具有不同扩展名的多个文件？ [英] How to recursively delete multiple files with different extensions?

问题描述

我试图编写一个命令，从当前目录及其所有相关的子目录递归地删除具有不同扩展名（* .extension1，* .extension2等）的几个文件。

I am trying to write a command to remove recursively several files with different extensions (*.extension1, *.extension2 etc) from the current directory and all its related sub-directories.

到目前为止，我从，但我不能锻炼如何适应它在同一命令行中的多个文件：

So far I got this command from another post but I couldn't workout how to adapt it to more than one file in the same command line:

find . -name "*.extension1" -type f -delete

是否如下简单？ p>

Is it as simple as below?

find . -name "*.extension1";"*.extension2" -type f -delete

这些都是我不需要的输出文件，但并不是所有输出文件都必须始终输出，因此有些扩展名可能不存在。这只是一个普通的清理命令。

Just as a side note, these are all output files that I do not need, but not all are necessarily always output so some of the extensions might not be present. This is just as a general clean-up command.

推荐答案

find . \( -name "*.extension1" -o -name "*.extension2" \) -type f -delete

find文件（-name .py-o -name .html）--exec文件{} \;

find Documents ( -name ".py" -o -name ".html" ) -exec file {} \;

OR

find . -regextype posix-egrep -regex ".*\.(extension1|extension2)$" -type f -delete

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