在Firebase的Cloud Functions中从数据库中获取用户标识？ [英] Getting the user id from a database trigger in Cloud Functions for Firebase?

问题描述

在下面的例子中，是否有一种方法可以获得写给/ messages / {pushId} / original的用户的uid？

  exports.makeUppercase = functions.database.ref（'/ messages / {pushId} / original'）
 .onWrite（event => {
 //获取当前的值写入实时数据库
 const original = event.data.val（）; 
 console.log（'Uppercasing'，event.params.pushId，original）; 
 const uppercase = original.toUpperCase（）; 
 //当在
函数中执行异步任务时，必须返回一个Promise 
 //设置一个大写在实时数据库中的兄弟会返回一个Promise。
 return event.data.ref.parent.child（'uppercase'）.set（uppercase）; 
}）; 
  

解决方案

是的，这在技术上是可行的，目前记录。 uid 存储在 event.auth 对象中。从管理员情况（例如，从Firebase控制台数据查看器或Admin SDK）触发数据库云端功能时， event.auth 的值为：

  {
admin：true 
} 
  

当从未经身份验证的引用触发数据库云端函数时， event.data 的值为：

  {
admin：false 
} 
  

$ b 最后，当一个数据库云端函数从一个authed而非admin的引用触发时， event.auth的格式是：

  {
admin：false，
variable ：{
provider：< PROVIDER>，
provider_id：< PROVIDER>，
user_id：< UID& $ btoken：{
 //解码的授权令牌声明，例如sub，aud，iat，exp等
}，
uid：< UID> 
 
 
 
 
 
 
 $ b给出上面的信息，触发该事件的用户的 uid 执行以下操作： 
 
 
  exports.someFunction = functions.database.ref（'/ some / path'）
 .onWrite（event => {
 var isAdmin = event.auth.admin; 
 var uid = event.auth.variable？event.auth.variable.uid：null; 
 
 // ... 
}）; 
  
请注意，在上面的代码中， uid 即使 isAdmin 是 true ，也会是 null 。您的确切代码取决于您的用例。
 
 
 
 警告：这是目前没有记录的行为，所以我会给我通常的警告无证功能可能会在未来的任何时候改变，恕不另行通知，甚至在非主要版本。
 
In the example below, is there a way to get the uid of the user who wrote to /messages/{pushId}/original?
exports.makeUppercase = functions.database.ref('/messages/{pushId}/original')
.onWrite(event => {
  // Grab the current value of what was written to the Realtime Database.
  const original = event.data.val();
  console.log('Uppercasing', event.params.pushId, original);
  const uppercase = original.toUpperCase();
  // You must return a Promise when performing asynchronous tasks inside a Functions such as
  // writing to the Firebase Realtime Database.
  // Setting an "uppercase" sibling in the Realtime Database returns a Promise.
  return event.data.ref.parent.child('uppercase').set(uppercase);
});

解决方案
Yes, this is technically possible, although it is not currently documented. The uid is stored with the event.auth object. When a Database Cloud Function is triggered from an admin situation (for example, from the Firebase Console data viewer or from an Admin SDK), the value of event.auth is:
{
  "admin": true
}
When a Database Cloud Function is triggered from an unauthenticated reference, the value of event.data is:
{
  "admin": false
}
And finally, when a Database Cloud Function is triggered from an authed, but not admin, reference, the format of event.auth is:
{
  "admin": false,
  "variable": {
    "provider": "<PROVIDER>",
    "provider_id": "<PROVIDER>",
    "user_id": "<UID>",
    "token": {
      // Decoded auth token claims such as sub, aud, iat, exp, etc.
    },
    "uid": "<UID>"
  }
}
Given the information above, your best bet to get the uid of the user who triggered the event is to do the following:
exports.someFunction = functions.database.ref('/some/path')
  .onWrite(event => {
    var isAdmin = event.auth.admin;
    var uid = event.auth.variable ? event.auth.variable.uid : null;

    // ...
});
Just note that in the code above, uid would be null even if isAdmin is true. Your exact code depends on your use case.

WARNING: This is currently undocumented behavior, so I'll give my usual caveat of "undocumented features may be changed at any point in the future without notice and even in non-major releases."

                        
这篇关于在Firebase的Cloud Functions中从数据库中获取用户标识？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！