安卓:正确的方法使用onBack pressed() [英] Android: Proper Way to use onBackPressed()
问题描述
我写了一张code,会给用户一个提示,询问他们preSS回来,如果他们想退出。目前,我有我的code工作的程度,但我知道它是写得不好,我想有一个更好的方式来做到这一点。任何建议将是有益的!
code:
公共无效onBack pressed(){
回到preSS =(回preSS + 1);
Toast.makeText(getApplicationContext(),再度回到preSS以退出,Toast.LENGTH_SHORT).show();
如果(背面preSS→1){
this.finish();
}
}
我想实现一个对话框,询问用户是否想退出,然后调用pssed super.onBack $ P $(),如果他们做到了。
@覆盖
公共无效onBack pressed(){
新AlertDialog.Builder(本)
.setTitle(真的退出?)
.setMessage(你确定要退出吗?)
.setNegativeButton(android.R.string.no,空)
.setPositiveButton(android.R.string.yes,新OnClickListener(){
公共无效的onClick(DialogInterface为arg0,INT ARG1){
WelcomeActivity.super.onBack pressed();
}
})创建()显示()。
}
在上面的例子中,你需要与你的活动的名称替换WelcomeActivity。
I wrote a piece of code that will give the user a prompt asking them to press back again if they would like to exit. I currently have my code working to an extent but I know it is written poorly and I assume there is a better way to do it. Any suggestions would be helpful!
Code:
public void onBackPressed(){
backpress = (backpress + 1);
Toast.makeText(getApplicationContext(), " Press Back again to Exit ", Toast.LENGTH_SHORT).show();
if (backpress>1) {
this.finish();
}
}
I would implement a dialog asking the user if they wanted to exit and then call super.onBackPressed() if they did.
@Override
public void onBackPressed() {
new AlertDialog.Builder(this)
.setTitle("Really Exit?")
.setMessage("Are you sure you want to exit?")
.setNegativeButton(android.R.string.no, null)
.setPositiveButton(android.R.string.yes, new OnClickListener() {
public void onClick(DialogInterface arg0, int arg1) {
WelcomeActivity.super.onBackPressed();
}
}).create().show();
}
In the above example, you'll need to replace WelcomeActivity with the name of your activity.
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