如何将一个childNode从一个节点复制到另一个节点？ [英] How to copy a childNode from one node to another?

问题描述

$ p
$ b

我需要下载childNode，然后将其设置（）到另一个节点中。

b
$ b

问题是我只想在childNode的score属性达到100的时候这样做。

何时何地应该检查帖子是否有100分或更高的分数，如何将它们复制到新的索引只有一次？

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什么想法：

当一篇文章被加载，检查它的分数。如果大于等于100，则检查数据库是否如此。然后将节点推到新的索引。

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问题：

我怎样才能防止节点每次加载后上传，因为它在多个负载上的得分大于等于100？我需要它只发生一次！

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解决方案代码：

  if（funPost.score> = global.hotNumber&& funPost.hot == false）{
 var hotPostRef = firebase。 。数据库（）REF（ 热/部分/ +键）; 
 var hotPost = {
 title：funPost.title，
 image：funPost.image，
 id：funPost.id，
 key：funPost.key 
} 
 hotPostRef.set（hotPost）; 
 funPostRef.update（{hot：true}）; 
} 
 else if（funPost.score< =（global.hotNumber  -  25）&& funPost.hot == true）{
 var hotPostRef = firebase.database（）。 REF（ 热/部分/ +键）; 
 hotPostRef.remove（）; 
 funPostRef.update（{hot：false}）; 
 
 
 
 
 
 
解决方案：我结束了使用布尔标志。
解决方案
最后，我用一个布尔标志来做：
 
 
  if（funPost.score> = global.hotNumber&& funPost.hot == false）{
 var hotPostRef = firebase.database（）。 REF（ 热/部分/ +键）; 
 var hotPost = {
 title：funPost.title，
 image：funPost.image，
 id：funPost.id，
 key：funPost.key 
} 
 hotPostRef.set（hotPost）; 
 funPostRef.update（{hot：true}）; 
} 
 else if（funPost.score< =（global.hotNumber  -  25）&& funPost.hot == true）{
 var hotPostRef = firebase.database（）。 REF（ 热/部分/ +键）; 
 hotPostRef.remove（）; 
 funPostRef.update（{hot：false}）; 
} 
  
 
SITUATION:

I would need to download the childNode, then set() it into the other node.

Problem is I want to do this only once the childNode's score attribute reaches 100.

Where and when should I check if posts have a score of 100 or more and how would I copy them to the new index only once ?



WHAT I THOUGHT OF:

When a post is loaded, check for it's score. If it's >= 100, check in the database if that's the case. Then push the node to the new index. 



PROBLEM:

How would I prevent the node from being uploaded each time the post is loaded since it's score is >= 100 on multiple loads ? I need it to happen only once !



SOLUTION CODE:
if (funPost.score >= global.hotNumber && funPost.hot == false) {
            var hotPostRef = firebase.database().ref("hot/section/"+key);
            var hotPost = {
                title: funPost.title,
                image: funPost.image,
                id: funPost.id,
                key: funPost.key
            }
            hotPostRef.set(hotPost);
            funPostRef.update({"hot": true});
        }
   else if (funPost.score <= (global.hotNumber - 25) && funPost.hot == true) {
        var hotPostRef = firebase.database().ref("hot/section/"+key);
        hotPostRef.remove();
        funPostRef.update({"hot": false});
   }




Solution: I ended up using a boolean flag.
解决方案
I ended up doing it with a boolean flag:
if (funPost.score >= global.hotNumber && funPost.hot == false) {
            var hotPostRef = firebase.database().ref("hot/section/"+key);
            var hotPost = {
                title: funPost.title,
                image: funPost.image,
                id: funPost.id,
                key: funPost.key
            }
            hotPostRef.set(hotPost);
            funPostRef.update({"hot": true});
        }
   else if (funPost.score <= (global.hotNumber - 25) && funPost.hot == true) {
        var hotPostRef = firebase.database().ref("hot/section/"+key);
        hotPostRef.remove();
        funPostRef.update({"hot": false});
   }


                        
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