Firebase将用户身份验证链接到其他活动 [英] Firebase link user authentication to another activity
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问题描述
我有一个用户通过Firebase使用一项活动登录我的应用程序，我可以在下一个活动中访问用户的详细信息。例如：
登录类：
public class LoginActivity extends AppCompatActivity {
EditText editText;
EditText editText2;
按钮按钮;
public FirebaseAuth Auth = FirebaseAuth.getInstance（）;
public FirebaseAuth.AuthStateListener authlistener;
字符串电子邮件，通过;
ProgressBar栏;
$ b $ public View.OnClickListener buttonListener = new View.OnClickListener（）{$ b $ public void onClick（View view）{
email = editText.getText（）。toString（）。trim （）;
pass = editText2.getText（）。toString（）。trim（）;
logInUser（）;
}};
@Override
protected void onCreate（Bundle savedInstanceState）{
super.onCreate（savedInstanceState）;
setContentView（R.layout.activity_main）;
editText =（EditText）findViewById（R.id.editText）;
editText2 =（EditText）findViewById（R.id.editText2）;
button =（Button）findViewById（R.id.button2）;
Auth = FirebaseAuth.getInstance（）;
button.setOnClickListener（buttonListener）;
bar =（ProgressBar）findViewById（R.id.progressBar2）;
bar.setVisibility（View.INVISIBLE）;
$ b authlistener = new FirebaseAuth.AuthStateListener（）{
@Override $ b $ public void onAuthStateChanged（@NonNull FirebaseAuth firebaseAuth）{
FirebaseUser user = firebaseAuth.getCurrentUser（）;
if（user！= null）{
//用户已登录
} else {
//用户退出
}
// ...
}
};
// ...
}
@Override
public void onStart（）{
super.onStart（）;
Auth.addAuthStateListener（authlistener）;
@Override
public void onStop（）{
super.onStop（）;
if（authlistener！= null）{
Auth.removeAuthStateListener（authlistener）;
public void logInUser（）{
bar.setVisibility（View.VISIBLE）;
Auth.signInWithEmailAndPassword（email，pass）
.addOnCompleteListener（this，new OnCompleteListener< AuthResult>（）{
@Override
public void onComplete（@NonNull Task< ; AuthResult>任务）{
if（task.isSuccessful（））{
Intent loggedInActivity = new Intent（getApplicationContext（），Loggedin.class）;
startActivity（loggedInActivity）;
else {
Toast.makeText（getApplicationContext（），出错了，再试一次，Toast.LENGTH_SHORT） .show（）;
}
}
}）;
$ b 登录到Activity：
public class Loggedin extends AppCompatActivity {
Button changeMail，changePass ;
字符串oldPassword;
String newPassword;
EditText oldpass，newpass;
FirebaseUser user = FirebaseAuth.getInstance（）。getCurrentUser（）;
public FirebaseAuth Auth = FirebaseAuth.getInstance（）;
public void updatePassword（）{
oldPassword = oldpass.getText（）。toString（）;
newPassword = newpass.getText（）。toString（）;
$ @覆盖
保护无效的onCreate（Bundle savedInstanceState）{
super.onCreate（savedInstanceState）;
setContentView（R.layout.activity_loggedin）;
changeMail =（Button）findViewById（R.id.changeMail）;
changePass =（Button）findViewById（R.id.changePass）;
oldpass =（EditText）findViewById（R.id.oldPass）;
newpass =（EditText）findViewById（R.id.newPass）;
oldpass.setVisibility（View.INVISIBLE）;
newpass.setVisibility（View.VISIBLE）;
$ b code
$ b 假设我想更改密码用户在 loggedinClass 中。我必须使用 login.class 中的意图，然后使用中的 code> loggedin 类而不是login.class。
但是如果我有多个活动，这将是繁琐的，签名如果你把一个 AuthStateListener 放在每一个活动中？
解决方案其他类，您可以检测到用户的登录状态，而不需要他们再次登录。 authlistener = new FirebaseAuth .AuthStateListener（）{
@Override
public void onAuthStateChanged（@NonNull FirebaseAuth firebaseAuth）{
FirebaseUser user = firebaseAuth.getCurrentUser（）;
if（user！= null）{
//用户已登录
} else {
//用户退出
}
// ...
}
};
FirebaseAuth.getInstance（）。addAuthStateListener（authListener）;
I have say a user who signs in to my app using one activity via Firebase, can I access the user's details in the next activity. Eg:
Login class:
public class LoginActivity extends AppCompatActivity {
EditText editText;
EditText editText2;
Button button;
public FirebaseAuth Auth = FirebaseAuth.getInstance();
public FirebaseAuth.AuthStateListener authlistener;
String email, pass;
ProgressBar bar;
public View.OnClickListener buttonListener = new View.OnClickListener() {
public void onClick (View view){
email = editText.getText().toString().trim();
pass = editText2.getText().toString().trim();
logInUser();
}};
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
editText = (EditText)findViewById(R.id.editText);
editText2 = (EditText)findViewById(R.id.editText2);
button = (Button)findViewById(R.id.button2);
Auth = FirebaseAuth.getInstance();
button.setOnClickListener(buttonListener);
bar = (ProgressBar)findViewById(R.id.progressBar2);
bar.setVisibility(View.INVISIBLE);
authlistener = new FirebaseAuth.AuthStateListener() {
@Override
public void onAuthStateChanged(@NonNull FirebaseAuth firebaseAuth) {
FirebaseUser user = firebaseAuth.getCurrentUser();
if (user != null) {
// User is signed in
} else {
// User is signed out
}
// ...
}
};
// ...
}
@Override
public void onStart() {
super.onStart();
Auth.addAuthStateListener(authlistener);
}
@Override
public void onStop() {
super.onStop();
if (authlistener != null) {
Auth.removeAuthStateListener(authlistener);
}
}
public void logInUser(){
bar.setVisibility(View.VISIBLE);
Auth.signInWithEmailAndPassword(email, pass)
.addOnCompleteListener(this, new OnCompleteListener<AuthResult>() {
@Override
public void onComplete(@NonNull Task<AuthResult> task) {
if(task.isSuccessful()) {
Intent loggedInActivity = new Intent(getApplicationContext(), Loggedin.class);
startActivity(loggedInActivity);
}
else{
Toast.makeText(getApplicationContext(), "There was an error, try again", Toast.LENGTH_SHORT).show();
}
}
});
}
}
Logged in Activity:
public class Loggedin extends AppCompatActivity {
Button changeMail, changePass;
String oldPassword;
String newPassword;
EditText oldpass, newpass;
FirebaseUser user = FirebaseAuth.getInstance().getCurrentUser();
public FirebaseAuth Auth = FirebaseAuth.getInstance();
public void updatePassword(){
oldPassword = oldpass.getText().toString();
newPassword = newpass.getText().toString();
}
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_loggedin);
changeMail = (Button)findViewById(R.id.changeMail);
changePass = (Button)findViewById(R.id.changePass);
oldpass = (EditText)findViewById(R.id.oldPass);
newpass = (EditText)findViewById(R.id.newPass);
oldpass.setVisibility(View.INVISIBLE);
newpass.setVisibility(View.VISIBLE);
}
}
Say I want to change the password of the user in the loggedinClass. Do I have to uses the intent from the "login.class" and then use the sign in method in the loggedin class rather than the login.class.
but what if I had multiple activities, this would get tedious, signing in to every activity?
解决方案 If you put an AuthStateListener in the other classes, you can detect the sign-in state of the user without requiring them to sign in again.
authlistener = new FirebaseAuth.AuthStateListener() {
@Override
public void onAuthStateChanged(@NonNull FirebaseAuth firebaseAuth) {
FirebaseUser user = firebaseAuth.getCurrentUser();
if (user != null) {
// User is signed in
} else {
// User is signed out
}
// ...
}
};
FirebaseAuth.getInstance().addAuthStateListener(authListener);
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