XSL中的特殊字符 [英] Special characters in XSL
问题描述
我正在进行XSL 1.0转换，以在Firefox中显示XML时获得HTML可视化。
在我的原始XML中，我有像
& amp; eacute; &放大器;放大器; egrave; & amp; lsquo; ...
我需要将它们转换为
é，è，'...
我已经使用了这个模板：
< xsl：template name =string-replace-all> ;
< xsl：param name =text/>
< xsl：param name =replace/>
< xsl：param name =by/>
< xsl：value-of select =substring-before（$ text，$ replace）/>
< xsl：value-of select =$ by/>
< xsl：call-template name =string-replace-all>
< xsl：with-param name =textselect =substring-after（$ text，$ replace）/>
< / xsl：when>
< xsl：otherwise>
< xsl：value-of select =$ text/>
< / xsl：否则>
调用每个特殊字符（例如& egrave;）：
< xsl：variable name =newtext>
< xsl：call-template name =string-replace-all>
< xsl：with-param name =textselect =$ originaltext/>
< / xsl：variable>
有没有解决方法可以直接替换& amp; code>放入&例如，不需要为每个特殊字符调用替换模板，我希望存在？
这似乎适用于我（旧版本）Firefox：
XML
<？xml version =1.0encoding =utf-8？>
<？xml-stylesheet type =text / xslhref =mystyle.xsl？>
< root>
< description>包含逃逸物件的文章< / description>
Lor& eacute; m ipsum& amp; amp; amp; amp; amp; amp; amp; amp; amp; amp; amp; amp; amp; amp; amp; amp; amp; amp; amp; amp; amp; amp; amp; amp; $ amp;坐在& egrave; t，consectetuer adipiscing elit。< / content>
< / root>
mystyle.xsl
< xsl：stylesheet version =1.0
xmlns：xsl =http://www.w3.org/1999/XSL/Transform>
< xsl：template match =/ root>
< html>
< body>
< h2>< xsl：value-of select =description/>< / h2>
< p id =content>
< xsl：value-of select =content/>
< / p>
< script>
var element = document.getElementById（content）;
element.innerHTML = element.innerHTML.replace（/& amp; / g，'& amp;'）;
< / script>
< / body>
< / html>
< / xsl：template>
< / xsl：stylesheet>
结果（屏幕截图）： b $ b
警告：我不是Javascript专家;这只是我冲动拼凑在一起的东西。
I'm working on a XSL 1.0 transformation to get HTML visualisation when displaying the XML in Firefox. In my original XML, I have characters like
&eacute; &egrave; &lsquo;...
I need to convert them into
é, è, ‘...
I have used this template :
<xsl:template name="string-replace-all">
<xsl:param name="text" />
<xsl:param name="replace" />
<xsl:param name="by" />
<xsl:choose>
<xsl:when test="contains($text, $replace)">
<xsl:value-of select="substring-before($text,$replace)" />
<xsl:value-of select="$by" />
<xsl:call-template name="string-replace-all">
<xsl:with-param name="text" select="substring-after($text,$replace)" />
<xsl:with-param name="replace" select="$replace" />
<xsl:with-param name="by" select="$by" />
</xsl:call-template>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="$text" />
</xsl:otherwise>
</xsl:choose>
Calling for each special character (here for example è) :
<xsl:variable name="newtext">
<xsl:call-template name="string-replace-all">
<xsl:with-param name="text" select="$originaltext" />
<xsl:with-param name="replace" select="'&egrave;'" />
<xsl:with-param name="by" select="'è'" />
</xsl:call-template>
</xsl:variable>
Is there a solution where I can directly replace & into & for example without the need to call the replacement template for each special character I expect to exist?
This seems to work for me in (an old version of) Firefox:
XML
<?xml version="1.0" encoding="utf-8"?>
<?xml-stylesheet type="text/xsl" href="mystyle.xsl"?>
<root>
<description>Article Containing Escaped Entitites</description>
<content>Lor&eacute;m ipsum &lsquo;dolor&lsquo; sit am&egrave;t, consectetuer adipiscing elit.</content>
</root>
mystyle.xsl
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/root">
<html>
<body>
<h2><xsl:value-of select="description"/></h2>
<p id="content">
<xsl:value-of select="content"/>
</p>
<script>
var element = document.getElementById("content");
element.innerHTML = element.innerHTML.replace(/&amp;/g,'&');
</script>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
Result (screenshot):
Caveat: I am not a Javascript expert; this is just something I cobbled together on impulse.
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