从Flash保存图像，发送给PHP，并返回一个URL字符串到Flash [英] Save image from Flash, send it to PHP and return a URL string to Flash

问题描述

我使用这段代码将图像转换为BitmapData，并将JPG存储在ByteArray中。

  import com.adobe .images.JPGEncoder; 
 
 var jpgSource：BitmapData = new BitmapData（img_mc.width，img_mc.height）; 
 jpgSource.draw（img_mc）; 
 
 var jpgEncoder：JPGEncoder = new JPGEncoder（85）; 
 var jpgStream：ByteArray = jpgEncoder.encode（jpgSource）; 
 
 //这里我们需要一些代码来发送bytearray，但是我缺乏足够的知识来做自己的
  

现在，我想要执行以下操作：
1.将ByteArray发送给PHP;
2. PHP必须在服务器上存储物理image_id.jpg;
3.那么PHP必须将图像的URL返回给Flash;

这可能吗？如何？

PHP的第一行可能是：
$ b $ pre $ if （isset（$ GLOBALS [HTTP_RAW_POST_DATA]））
{
// get bytearray
$ jpg = $ GLOBALS [HTTP_RAW_POST_DATA];

//但我不知道如何将图像保存在磁盘上，以及如何返回// image的网址
}


谢谢！

解决方案

as3部分：

  
 import com.adobe.images.JPGEncoder; 
 import flash.events.Event; 
 import flash.net.URLLoader; 
 import flash.net.URLRequestHeader; 
 import flash.net.URLRequest; 
 $ b $ var jpgSource：BitmapData = new BitmapData（img_mc.width，img_mc.height）; 
 jpgSource.draw（img_mc）; 
 var jpgEncoder：JPGEncoder = new JPGEncoder（85）; 
 var jpgStream：ByteArray = jpgEncoder.encode（jpgSource）; 
 
 
 //设置请求头，方法和数据
 var header：URLRequestHeader =新的URLRequestHeader（Content-type，application / octet-stream）; 
 var loader：URLLoader = new URLLoader（）; 
 //发送jpg字节到saveJPG.php脚本
 var myRequest：URLRequest = new URLRequest（saveJPG.php）; 
 myRequest.requestHeaders.push（header）; 
 myRequest.method = URLRequestMethod.POST; 
 myRequest.data = jpgStream; 
 loader.load（myRequest）; 
 //火灾完成事件; 
 loader.addEventListener（Event.COMPLETE，saved）; 
函数保存（e：Event）
 {
 //跟踪图像文件名
 trace（loader.data）; 
 
 $ / pre $ 
 $ b 
 php（saveJPG.php）部分：
 
  
 if（isset（$ GLOBALS [HTTP_RAW_POST_DATA]））{
 
 
  //图像文件名
 $ fileName ='img.jpg'; 
 
 //获取二进制流
 $ im = $ GLOBALS [HTTP_RAW_POST_DATA]; 
 
 //写出
 $ fp = fopen（$ fileName，'wb'）; 
 fwrite（$ fp，$ im）; 
 fclose（$ fp）; 
 
 //回显fileName; 
 echo $ fileName; 
  
} else echo'result =发生错误。 
 
  
 
I use this code to convert an image to a BitmapData and store a JPG in a ByteArray.
import com.adobe.images.JPGEncoder;

var jpgSource:BitmapData = new BitmapData (img_mc.width, img_mc.height);
jpgSource.draw(img_mc);

var jpgEncoder:JPGEncoder = new JPGEncoder(85);
var jpgStream:ByteArray = jpgEncoder.encode(jpgSource);

// here we need some code to send the bytearray but I lack enough knowledge to do it by myself
Now, I want to do the following:
1. send the ByteArray to PHP;
2. PHP must store a physical image_id.jpg on server;
3. then PHP must return the URL of the image to Flash;

Is this possible? How?

The first lines of PHP could be:
if (isset($GLOBALS["HTTP_RAW_POST_DATA"]))
{
    // get bytearray
    $jpg = $GLOBALS["HTTP_RAW_POST_DATA"];

    // but I don't know how to save the image on disk and how to return the URL of the //image
}
Thanks!
解决方案
the as3 part:

import com.adobe.images.JPGEncoder;
import flash.events.Event;
import flash.net.URLLoader;
import flash.net.URLRequestHeader;
import flash.net.URLRequest;


var jpgSource:BitmapData = new BitmapData(img_mc.width,img_mc.height);
jpgSource.draw(img_mc);
var jpgEncoder:JPGEncoder = new JPGEncoder(85);
var jpgStream:ByteArray = jpgEncoder.encode(jpgSource);

//set the request's header,method and data
var header:URLRequestHeader = new URLRequestHeader("Content-type","application/octet-stream");
var loader:URLLoader = new URLLoader();
//sends jpg bytes to saveJPG.php script
var myRequest:URLRequest = new URLRequest("saveJPG.php");
myRequest.requestHeaders.push(header);
myRequest.method = URLRequestMethod.POST;
myRequest.data = jpgStream;
loader.load(myRequest);
//fire complete event;
loader.addEventListener(Event.COMPLETE,saved);
function saved(e:Event)
{
    //trace the image file name
    trace(loader.data);
}


the php (saveJPG.php) part:

if ( isset ( $GLOBALS["HTTP_RAW_POST_DATA"] )) {
//the image file name   
$fileName = 'img.jpg';

// get the binary stream
$im = $GLOBALS["HTTP_RAW_POST_DATA"];

//write it
$fp = fopen($fileName, 'wb');
fwrite($fp, $im);
fclose($fp);

//echo the fileName;
echo $fileName;
}  else echo 'result=An error occured.';


                        
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