AS3如何转动矢量列表的头部？ [英] AS3 How to i turn head of the Vector list?

问题描述

我有一个矢量为IP和端口列表和套接字连接，当连接失去我点击按钮，并从矢量列表调用下一个IP和端口。

我的问题是什么时候完成我的列表如何我打开列表头？

这是我目前的代码

  public class UriIterator 
 {
 private var _availableAddresses：Vector。< SocketConnection> = new Vector。< SocketConnection>（）; 
 
 $ b public function UriIterator（）
 {
 
} 
 
 
公共函数withAddress（host：String ，port：int）：UriIterator {
 const a：SocketConnection = new SocketConnection（host，port）; 
 _availableAddresses.push（a）; 
返回这个; 
} 
 
 public function get next（）：SocketConnection {
 return _availableAddresses.length？ _availableAddresses.pop（）：null; 
 
 
 code 
 
 
 
谢谢 
 
 
 
  public class UriIterator 
 {
 private var _currentIndex：int = 0; 
 private var _availableAddresses：Vector。< SocketConnection> = new Vector。< SocketConnection>（）; 
 
 $ b $ public function withAddress（host：String，port：int）：UriIterator {
 const a：SocketConnection = new SocketConnection（host，port）; 
 _availableAddresses.push（a）; 
返回这个; 
 
 
 public function get first（）：SocketConnection {
 _currentIndex = 0; 
 if（_currentIndex> = _availableAddresses.length）
 return null; 
 return _availableAddresses [_currentIndex ++]; 
} 
 
 public function get next（）：SocketConnection {
 if（_currentIndex> = _availableAddresses.length）
 return null; 
 return _availableAddresses [_currentIndex ++]; 
 
 
 
 
 
 
现在得到第一个条目， $ c> const firstConn：SocketConnection = iterator.first 并获取其余的，只要继续调用 iterator.next 即可。  
I have a Vector for ip and port list and socket connection, When connection lose i click button and call the next ip and port from vector list.

My question is when finish my list how to  i turn head of the list ?

This my current code
public class UriIterator 
{
     private var _availableAddresses: Vector.<SocketConnection> = new Vector.<SocketConnection>();


    public function UriIterator() 
    {

    }


    public function withAddress(host: String, port: int): UriIterator {
        const a: SocketConnection = new SocketConnection(host, port);
        _availableAddresses.push(a);
        return this;
    }

     public function get next(): SocketConnection{
        return _availableAddresses.length ? _availableAddresses.pop() : null;
    }
}
Thanks
解决方案
In current implementation you can traverse the list only once. You need to change the code to keep the list unmodified: 
public class UriIterator 
{
    private var _currentIndex:int = 0;
    private var _availableAddresses: Vector.<SocketConnection> = new Vector.<SocketConnection>();


    public function withAddress(host: String, port: int): UriIterator {
        const a: SocketConnection = new SocketConnection(host, port);
        _availableAddresses.push(a);
        return this;
    }

    public function get first():SocketConnection {
        _currentIndex = 0;
        if (_currentIndex >= _availableAddresses.length) 
            return null;
        return _availableAddresses[_currentIndex++];
   }

   public function get next(): SocketConnection {
        if (_currentIndex >= _availableAddresses.length) 
            return null;
        return _availableAddresses[_currentIndex++];
   }
}
Now to get the first entry you call const firstConn:SocketConnection = iterator.first and to get the rest of them, just keep calling iterator.next.  

                        
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