如何在python中使用瓶子上传多个文件 [英] how to upload multiple files using flask in python

问题描述

pre> 浏览< input type =filename =pro_attachment1id =pro_attachment1multiple>


PYTHON CODE：

  pro_attachment = request.files.getlist（'pro_attachment1'）
 
在pro_attachment中上传：
 filename = upload.filename.rsplit /）[0] 
 destination = os.path.join（application.config ['UPLOAD_FOLDER']，filename）
打印接受传入文件：，文件名
打印保存它到：，目标
 upload.save（目的地）
  

但它上传一个单文件而不是多个文件。

解决方案

如何

模板，您需要在上传输入中添加 mulitple 属性：

 < ; form method =POSTenctype =multipart / form-data> 
< input type =filename =photosmultiple> 
< input type =submitvalue =Submit> 
< / form> 
  

然后在view函数中，上传的文件可以通过请求.files.getlist（ '照片'）。循环播放列表并调用 save（）方法在每个项目上（ werkzeug.datastructures.FileStorage ）将保存在给定的路径：

  import os 
 $ b $ from flask flask Flask，request，render_template，redirect 
 $ b app = Flask（__ name__）
 app.config ['UPLOAD_PATH'] ='\static\uploads'
 
 @ app.route（'/上传'，方法= ['GET'，'POST']）
 def upload（）：$ b $如果request.method =='POST'和'photo'request.files：
 for f in request.files.getlist（'photo'）：
 f.save（os.path.join（app.config ['UPLOAD_PATH']，f.filename））
 return'Upload completed '
返回render_template（'upload.html'）
  

此外，您可能需要使用 secure_filename（）到 clean 文件名：

 <$ c $从$ werkzeug.utils导入secure_filename 
 $ ... 
 for $ request.files.getlist（'photo'）：
 filename = secure_filename f.filename）
 f.save（os.path.join（app.config ['UPLOAD_PATH']，filename））
＃... 
  

您也可以用这个方法

完整演示

查看：

进口os 
 $ b $从瓶子进口Flask，request，render_template __name__）
 app.config ['UPLOAD_PATH'] ='\static\uploads'
 
 @ main.route（'/ upload'，方法= ['GET'，'POST']）
 def upload（）：
 form = UploadForm（）
如果request.files中的form.validate_on_submit（）和'photo' b.files.getlist（'photo'）：
 filename = secure_filename（f.filename）
 f.save（os.path.join（app.config ['UPLOAD_PATH' ]，文件名））
 return'Upload completed。'
 return render_template（'upload.html'，form = form）
  

$ b $ p

$ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $' b $ b from flask_wtf.file import FileField，FileAllowed，FileRequired
$ b $ class UploadForm（FlaskForm）：
photo = FileField（'Image'，validators = [
FileRequired（），
FileAllowed（照片，仅限图片！）
]）
submit = SubmitField（'Submit'）

Template：

 < form method =POSTenctype =multipar吨/格式数据> 
 {{form.hidden_​​tag（）}} 
 {{form.photo（multiple =multiple）}} 
 {{form.submit}} 
< / form> ; 
  

更多

为了获得更好的上传体验，你可以尝试 Flask-Dropzone 。

Here is my code for multiple files upload:

HTML CODE:

Browse <input type="file" name="pro_attachment1" id="pro_attachment1" multiple>

PYTHON CODE:

pro_attachment = request.files.getlist('pro_attachment1')

for upload in pro_attachment:
    filename = upload.filename.rsplit("/")[0]
    destination = os.path.join(application.config['UPLOAD_FOLDER'], filename)
    print "Accept incoming file:", filename
    print "Save it to:", destination
    upload.save(destination)

But it uploads a single file instead of multiple files.

解决方案

How to

In the template, you need to add mulitple attribute in upload input:

<form method="POST" enctype="multipart/form-data">
    <input type="file" name="photos" multiple>
    <input type="submit" value="Submit">
</form>    

Then in view function, the uploaded files can get as a list through request.files.getlist('photos'). Loop this list and call save() method on each item (werkzeug.datastructures.FileStorage) will save them at given path:

import os

from flask import Flask, request, render_template, redirect

app = Flask(__name__)
app.config['UPLOAD_PATH'] = '\static\uploads'

@app.route('/upload', methods=['GET', 'POST'])
def upload():
    if request.method == 'POST' and 'photo' in request.files:
        for f in request.files.getlist('photo'):
            f.save(os.path.join(app.config['UPLOAD_PATH'], f.filename))
        return 'Upload completed.'
    return render_template('upload.html')

Furthermore, you may need to use secure_filename() to clean filename:

# ...
from werkzeug.utils import secure_filename
# ...
    for f in request.files.getlist('photo'):
        filename = secure_filename(f.filename)
        f.save(os.path.join(app.config['UPLOAD_PATH'], filename))
        # ...

You can also generate a random filename with this method.

Full demo

View:

import os

from flask import Flask, request, render_template
from werkzeug.utils import secure_filename

app = Flask(__name__)  
app.config['UPLOAD_PATH'] = '\static\uploads'

@main.route('/upload', methods=['GET', 'POST'])
def upload():
    form = UploadForm()
    if form.validate_on_submit() and 'photo' in request.files:
        for f in request.files.getlist('photo'):
            filename = secure_filename(f.filename)
            f.save(os.path.join(app.config['UPLOAD_PATH'], filename))
        return 'Upload completed.'
    return render_template('upload.html', form=form)

Form:

from flask_wtf import FlaskForm
from wtforms import SubmitField
from flask_wtf.file import FileField, FileAllowed, FileRequired

class UploadForm(FlaskForm):
    photo = FileField('Image', validators=[
        FileRequired(),
        FileAllowed(photos, 'Image only!')
    ])
    submit = SubmitField('Submit')

Template:

<form method="POST" enctype="multipart/form-data">
    {{ form.hidden_tag() }}
    {{ form.photo(multiple="multiple") }}
    {{ form.submit }}
</form>

More

For better upload experience, you can try Flask-Dropzone.

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