简单的表单提交python [英] Simple form submit python

问题描述

我有一个简单的python应用程序，它使用post方法从html表单提交姓名和电话。
我在index.html有这个：

 < form action =http://127.0.0.1 ：5000 / get_phone /method =POST> 
名字：
< input type =textname =firstname> 
 
电话：
< input type =textname =lastname> 
 
< input type =submitvalue =Submit> 
< / form> 
  

有我的 getPhone.py ：

  from flask import Flask 
 app = Flask（__ name__）
 
 @ app.route（ ''get_phone /'，methods = ['POST'，'GET']）
 def get_phone（）：$ b $如果request.method =='POST'：
 print ：'，request.form ['firstname']）
 print（'Phone：'，request.form ['lastname']）
 
 return'看看你的终端！ 
 $ b $ if if __name__ =='__main__'：
 app.run（）
  

$ b $但是，当我提交我的表单，我在我的浏览器中收到以下消息：
$ b

内部服务器错误

服务器遇到内部错误，无法完成
的请求。或者服务器被重载，或
应用程序出现错误。

在我的控制台中，我有这个：

 > *运行在http://127.0.0.1:5000/（按CTRL + C退出）
 127.0.0.1  -   -  [04 / Feb / 2015 22:20:04]GET / get_phone / HTTP / 1.1 500  -  
 127.0.0.1  -   -  [04 / Feb / 2015 22:20:12]POST / get_phone / HTTP / 1.1500  -  
 127.0.0.1  -   -  [04 / Feb / 2015 22:26:22]GET / get_phone / HTTP / 1.1500  -  
  

如何解决这个问题
$ b

UPD：consoleLog with debug = true：

  *运行在http://127.0.0.1:5000/上（按CTRL + C退出）
 *用stat 
重新启动127.0.0.1  -   -  [04 / Feb / 2015 22:35:30]POST / get_phone / HTTP / 1.1500  -  
 Traceback（最近一次调用的最后一个）：
文件C：\ Python34\lib\site-packages\flask\app.py， 1836行，在__call__ 
返回self.wsgi_app（environ，start_response）
文件C：\Python34\lib\site-packages\flask\app.py，第1820行，在wsgi_app 
响应= self.make_response（self.handle_exception（e））
文件C：\Python34\lib\\ site-packages\flask\app.py，第1403行，在handle_except中
 ion 
 reraise（exc_type，exc_value，tb）
文件C：\Python34\lib\\ \\ site-packages \flask\_compat.py，第33行，重新评估
提高价值
文件C：\Python34\lib\site-packages\flask\app .py，第1817行，在wsgi_app 
 response = self.full_dispatch_request（）
文件C：\Python34\lib\site-packages\flask\app.py，行1477，在full_dispatch 
 _request 
 rv = self.handle_user_exception（e）
文件C：\Python34\lib\site-packages\flask\app.py，第1381行，在handle_user_e 
 xception 
 reraise（exc_type，exc_value，tb）
文件C：\Python34\lib\site-packages\flask\_compat.py ，第33行，重新
提高价值
文件C：\Python34\lib\site-packages\flask\app.py，1475行，在full_dispatch 
 _request 
 rv = self.dispatch_request（）
文件C：\Python34\lib\site-packages\flask\app.py，行1461，在dispatch_requ 
 est 
返回self.view_functions [rule.endpoint]（** req.view_args）
文件C：\ Users \\\
evernight\Desktop\visa + py\getPhone.py，第6行，在get_phone 
 
 if request.method =='POST'：
 NameError：名称'request'未定义
 127.0.0.1  -   -  [04 / Feb / 2015 22:35： 32]GET / get_phone /？__ debugger __ = yes& cmd = resou $ b $ r rce& f = style.css HTTP / 1.1200  -  
 127.0.0.1  -   -  [04 / Feb / 2015 22:35 ：32]GET / get_phone /？__ debugger __ = yes& cmd = resou $ b $ r rce& f = jquery.js HTTP / 1.1200  -  
 127.0.0.1  -   -  [04 / Feb / 2015 22： 35:33] GET / get_phone /？__ debugger __ = yes& cmd = resou $ b $ r rce& f = debugger.js HTTP / 1.1200  -  
 127.0.0.1  -   -  [04 / Feb / 2015 22 ：35：34] GET / get_phone /？__ debugger __ = yes& cmd = resou $ b $ r rce& f = ubuntu.ttf HTTP / 1.1200  -  
 127.0.0.1  -   -  [04 / Feb / 2015 22:35:34]GET / get_phone /？__ debugger __ = yes& cmd = resou 
 rce& f = console.png HTTP / 1.1200  -  
 127.0.0.1  -   -  [04 / Feb / 2015 22:35:34] GET / get_phone /？__ debugger __ = yes& cmd = resou 
 rce& f = source.png HTTP / 1.1200  -  
 127.0.0.1  -   -  [04 / Feb / 2015 22:35:35] GET / get_phone /？__ debugger __ = yes& cmd = resou 
 rce& f = console.png HTTP / 1.1200  -  
  

解决方案

问题在于您没有导入请求。
像这样：

  from flask import Flask，请求
  

I have simple python app which gets name and phone from html form submit using post method. I have this in my index.html:

<form action="http://127.0.0.1:5000/get_phone/" method = "POST">
First name:
<input type="text" name="firstname" >

Phone:
<input type="text" name="lastname" >

<input type="submit" value="Submit">
</form>

And have my getPhone.py:

from flask import Flask
app = Flask(__name__)

@app.route('/get_phone/', methods=['POST', 'GET'])
def get_phone():
    if request.method == 'POST':
        print ('First name:', request.form['firstname'])
        print ('Phone:', request.form['lastname'])

    return 'Take a look at your terminal!'

if __name__ == '__main__':
    app.run()

But when I submit my form with I get the following message in my browser:

Internal Server Error

The server encountered an internal error and was unable to complete your request. Either the server is overloaded or there is an error in the application.

In my console I have this:

>  * Running on http://127.0.0.1:5000/ (Press CTRL+C to quit)
127.0.0.1 - - [04/Feb/2015 22:20:04] "GET /get_phone/ HTTP/1.1" 500 -
127.0.0.1 - - [04/Feb/2015 22:20:12] "POST /get_phone/ HTTP/1.1" 500 -
127.0.0.1 - - [04/Feb/2015 22:26:22] "GET /get_phone/ HTTP/1.1" 500 -

How to fix this?

UPD: consoleLog with debug = true:

     * Running on http://127.0.0.1:5000/ (Press CTRL+C to quit)
 * Restarting with stat
127.0.0.1 - - [04/Feb/2015 22:35:30] "POST /get_phone/ HTTP/1.1" 500 -
Traceback (most recent call last):
  File "C:\Python34\lib\site-packages\flask\app.py", line 1836, in __call__
    return self.wsgi_app(environ, start_response)
  File "C:\Python34\lib\site-packages\flask\app.py", line 1820, in wsgi_app
    response = self.make_response(self.handle_exception(e))
  File "C:\Python34\lib\site-packages\flask\app.py", line 1403, in handle_except
ion
    reraise(exc_type, exc_value, tb)
  File "C:\Python34\lib\site-packages\flask\_compat.py", line 33, in reraise
    raise value
  File "C:\Python34\lib\site-packages\flask\app.py", line 1817, in wsgi_app
    response = self.full_dispatch_request()
  File "C:\Python34\lib\site-packages\flask\app.py", line 1477, in full_dispatch
_request
    rv = self.handle_user_exception(e)
  File "C:\Python34\lib\site-packages\flask\app.py", line 1381, in handle_user_e
xception
    reraise(exc_type, exc_value, tb)
  File "C:\Python34\lib\site-packages\flask\_compat.py", line 33, in reraise
    raise value
  File "C:\Python34\lib\site-packages\flask\app.py", line 1475, in full_dispatch
_request
    rv = self.dispatch_request()
  File "C:\Python34\lib\site-packages\flask\app.py", line 1461, in dispatch_requ
est
    return self.view_functions[rule.endpoint](**req.view_args)
  File "C:\Users\nevernight\Desktop\visa + py\getPhone.py", line 6, in get_phone

    if request.method == 'POST':
NameError: name 'request' is not defined
127.0.0.1 - - [04/Feb/2015 22:35:32] "GET /get_phone/?__debugger__=yes&cmd=resou
rce&f=style.css HTTP/1.1" 200 -
127.0.0.1 - - [04/Feb/2015 22:35:32] "GET /get_phone/?__debugger__=yes&cmd=resou
rce&f=jquery.js HTTP/1.1" 200 -
127.0.0.1 - - [04/Feb/2015 22:35:33] "GET /get_phone/?__debugger__=yes&cmd=resou
rce&f=debugger.js HTTP/1.1" 200 -
127.0.0.1 - - [04/Feb/2015 22:35:34] "GET /get_phone/?__debugger__=yes&cmd=resou
rce&f=ubuntu.ttf HTTP/1.1" 200 -
127.0.0.1 - - [04/Feb/2015 22:35:34] "GET /get_phone/?__debugger__=yes&cmd=resou
rce&f=console.png HTTP/1.1" 200 -
127.0.0.1 - - [04/Feb/2015 22:35:34] "GET /get_phone/?__debugger__=yes&cmd=resou
rce&f=source.png HTTP/1.1" 200 -
127.0.0.1 - - [04/Feb/2015 22:35:35] "GET /get_phone/?__debugger__=yes&cmd=resou
rce&f=console.png HTTP/1.1" 200 -

解决方案

The issue is that you haven't imported request. Like this:

from flask import Flask, request

这篇关于简单的表单提交python的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！