如何提取URL的特定部分并用不同的数据替换 [英] How to extract specific parts of a URL and replace with different data

问题描述

我有一个特定类型的网址，我需要确定它的一些部分，并用一些数据替换，url将是 www.something.com@param1 = {{^用户名^}}， param2 = {{^ user id ^}} ，....

我需要做的是识别 {{^ User Name ^}} 和 {{^ user id ^}} 并替换为我的值，

任何人有一个想法做这与flex？

我的一个朋友告诉我使用RegExp这个，但我

解决方案

像这样的东西可能会工作，没有RegExp专家。
$ b

  var s：String =www.something.com@param1={{ ^用户名称^}}，param2 = {{^ user id ^} }; 
 var userPattern：RegExp = /（？< = param1 =）（{{\ ^）（[A-Za-z0-9]）*（\ ^}}）/; 
 var userIdPattern：RegExp = /（？< = param2 =）（{{\ ^）（[A-Za-z0-9]）*（\ ^}}）/; 
 s = s.replace（userPattern，'username'）; 
 s = s.replace（userIdPattern，'user_id'）; 
  

如果您只想替换{{}} maby中的字符串，则会生效：

  var s：String =www.something.com@param1={{ ^用户名^}}，param2 = {{^ user ID ^}}; 
 var userPattern：RegExp = /（？< = param1 = {{）\ ^（[A-Za-z0-9]）* \ ^（？=}}）/; 
 var userIdPattern：RegExp = /（？< = param2 = {{）\ ^（[A-Za-z0-9]）* \ ^（？=}}）/; 
 s = s.replace（userPattern，'username'）; 
 s = s.replace（userIdPattern，'user_id'）; 
  

要移除多个{{}}，请执行以下操作www.something.com@param1={{用户名称^}}，{{^，e，^}}，paramX = {{^ user id ^}}在paramX之间试试这个：

  var s：String =www.something.com@param1={{ ^ User name ^}}，{{^，e，^}}，param2 = {{^ user id ^}}; 
 var userPattern：RegExp = /（？<= param1 = {{）\ ^（[A-Za-z0-9\ ^}} {{，]）*（？=}}）/ ; 
 var userIdPattern：RegExp = /（？<= param2 = {{）\ ^（[A-Za-z0-9\ ^}} {{，]）*（？=}}）/ ; 
 s = s.replace（userPattern，'username'）; 
 s = s.replace（userIdPattern，'user_id'）; 
  

输出应该是www.something.com@param1 = {{username}}，param2 = {{
$ b

$ b $ var s：String =www.something.com@param1={{ ^用户名^}}，{{^，e，^}}，param2 = {{^ user id ^}};
var userPattern：RegExp = /（？< = param1 =）（{{\ ^）（[A-Za-z0-9\ ^}} {{，]）*（}）/;
var userIdPattern：RegExp = /（？< = param2 =）（{{\ ^）（[A-Za-z0-9\ ^}} {{，]）*（}）/;
s = s.replace（userPattern，'username'）;
s = s.replace（userIdPattern，'user_id'）;


输出应该是www.something.com @ param1 = username，param2 = user_id。

I have a specific type url and i need to identify some parts of it and replace with some data, url would be www.something.com@param1={{^User Name^}},param2={{^user id^}},....

What i need to do is, identify {{^User Name^}} and {{^user id^}} and replace with my values,

Anybody have an idea to do this with flex?

A friend of mine told me to use RegExp for this, but I'm clueless about how to use it.

解决方案

Something like this might work, no expert on RegExp tho.

var s:String = "www.something.com@param1={{^User Name^}},param2={{^user id^}}";
var userPattern:RegExp = /(?<=param1=)({{\^)([A-Za-z0-9 ])*(\^}})/;
var userIdPattern:RegExp = /(?<=param2=)({{\^)([A-Za-z0-9 ])*(\^}})/;
s = s.replace(userPattern,'username');
s = s.replace(userIdPattern,'user_id');

If you want to replace only the string inside {{}} maby this would work:

var s:String = "www.something.com@param1={{^User Name^}},param2={{^user id^}}";
var userPattern:RegExp = /(?<=param1={{)\^([A-Za-z0-9 ])*\^(?=}})/;
var userIdPattern:RegExp = /(?<=param2={{)\^([A-Za-z0-9 ])*\^(?=}})/;
s = s.replace(userPattern,'username');
s = s.replace(userIdPattern,'user_id');

To remove multiple {{}} for exampe www.something.com@param1={{^User Name^}},{{^,e,^}},param2={{^user id^}} between paramX try this:

var s:String = "www.something.com@param1={{^User Name^}},{{^,e,^}},param2={{^user id^}}";
var userPattern:RegExp = /(?<=param1={{)\^([A-Za-z0-9\^}}{{, ])*(?=}})/;
var userIdPattern:RegExp = /(?<=param2={{)\^([A-Za-z0-9\^}}{{, ])*(?=}})/;
s = s.replace(userPattern,'username');
s = s.replace(userIdPattern,'user_id');

Output should be www.something.com@param1={{username}},param2={{user_id}}.

Another example:

var s:String = "www.something.com@param1={{^User Name^}},{{^,e,^}},param2={{^user id^}}";
var userPattern:RegExp = /(?<=param1=)({{\^)([A-Za-z0-9\^}}{{, ])*(})/;
var userIdPattern:RegExp = /(?<=param2=)({{\^)([A-Za-z0-9\^}}{{, ])*(})/;
s = s.replace(userPattern,'username');
s = s.replace(userIdPattern,'user_id');

Output should be www.something.com@param1=username,param2=user_id.

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