大多数Pythonic打印方式*最多*小数位数 [英] Most Pythonic way to print *at most* some number of decimal places
问题描述
4.001
=> 4
, 4.797 => 4.8
, 8.992
=> 8.99 , 13.577
=> code> 13.58
。
简单的解决方案是 ('%。2f'%f ).rstrip('。0')
('%。2f'%f).rstrip('0')。rstrip('。')
。但是,这看起来相当丑陋,似乎很脆弱。任何更好的解决方案,也许有一些神奇的格式标志?
解决方案您需要分开 0
code>和。
剥离;这样你就不会剥夺自然 0
。
或者,使用 format()
函数,但实际上归结为同一件事:
format(f ,'.2f')。rstrip('0')。rstrip('。')
测试:
>>> def format(f):return format(f,'.2f')。rstrip('0')。rstrip('。')
...
>>>格式化(0.0)
'0'
>>>格式化(4.797)
'4.8'
>>>格式化(4.001)
'4'
>>>格式化(13.577)
'13 .58'
>>>格式化(0.000000000000000000001)
'0'
>>>格式化(10000000000)
'10000000000'
I want to format a list of floating-point numbers with at most, say, 2 decimal places. But, I don't want trailing zeros, and I don't want trailing decimal points.
So, for example, 4.001
=> 4
, 4.797
=> 4.8
, 8.992
=> 8.99
, 13.577
=> 13.58
.
The simple solution is ('%.2f' % f).rstrip('.0')
('%.2f' % f).rstrip('0').rstrip('.')
. But, that looks rather ugly and seems fragile. Any nicer solutions, maybe with some magical format flags?
解决方案 You need to separate the 0
and the .
stripping; that way you won't ever strip away the natural 0
.
Alternatively, use the format()
function, but that really comes down to the same thing:
format(f, '.2f').rstrip('0').rstrip('.')
Some tests:
>>> def formatted(f): return format(f, '.2f').rstrip('0').rstrip('.')
...
>>> formatted(0.0)
'0'
>>> formatted(4.797)
'4.8'
>>> formatted(4.001)
'4'
>>> formatted(13.577)
'13.58'
>>> formatted(0.000000000000000000001)
'0'
>>> formatted(10000000000)
'10000000000'
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