Objective-C浮点四舍五入 [英] Objective-C Float Rounding

问题描述

示例：

  float f = 45.698f; 
 int rounded = _______; 
 NSLog（@四舍五入的浮点数是％i，舍入）; 
  

应该打印出四舍五入的浮点数为46

解决方案

推荐的方法是在这个答案： https://stackoverflow.com/a / 4702539/308315

---

原始答案：

<添加0.5后将其转换为int。

所以

  NSLog（@四舍五入的浮点数是％i，（int）（f + 0.5））; 
  

编辑：您要求的方式：

  int rounded =（f + 0.5）; 
 
 
 NSLog（@四舍五入的浮点数是％i，四舍五入）; 
  

How might I round a float to the nearest integer in Objective-C:

Example:

float f = 45.698f;
int rounded = _______;
NSLog(@"the rounded float is %i",rounded);

should print "the rounded float is 46"

解决方案

The recommended way is in this answer: https://stackoverflow.com/a/4702539/308315

---

Original answer:

cast it to an int after adding 0.5.

So

NSLog (@"the rounded float is %i", (int) (f + 0.5));

Edit: the way you asked for:

int rounded = (f + 0.5);


NSLog (@"the rounded float is %i", rounded);

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