打印__float128，不使用quadmath_snprintf [英] Print __float128, without using quadmath_snprintf

问题描述

在我的问题有关浮点数/双精度分析32位十进制数字，一个回答说看看 __ float128 。

我用它和编译器可以找到它，但是我不能打印它，因为编译器找不到头 quadmath.h 。

所以我的问题是：

1. __ float128 是标准的，正确吗？ / li>
   
2. 如何打印？


3. 不是 quadmath.h 标准吗？
>

这些答案没有帮助：

1. 使用 extern C


2. 在C ++中的精确性
a>





ref 也没有帮助。



注意我不想使用任何非标准库。
$ b




这也是有用的，如果这个问题有答案的话，即使答案是否定的也是如此。


解决方案 quadmath_snprintf 方法。在C ++中，当然可以使用< 。




In my question about Analysis of float/double precision in 32 decimal digits, one answer said to take a look at __float128.

I used it and the compiler could find it, but I can not print it, since the complier can not find the header quadmath.h.

So my questions are:

1. __float128 is standard, correct?
2. How to print it?
3. Isn't quadmath.h standard?

These answers did not help:

1. Use extern C
2. Precision in C++
3. Printing

The ref also did not help.

Note that I do not want to use any non standard library.

[EDIT]

It would be also useful, if that question had an answer, even if the answer was a negative one.

解决方案

No, it's not standard - neither the type nor the header. That's why the type has a double underscore (reserved name). Apparently, quadmath.h provides a quadmath_snprintf method. In C++ you would have used <<, of course.

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