编写一个程序，提示用户输入球体的半径并打印其体积 [英] Write a program that prompts the user for the radius of a sphere and prints its volume

问题描述

我没有得到正确的答案，下面的代码如下。任何人都可以调试此代码？
当我输入半径= 5时，我得到的答案是500.000000，而原来的答案应该是523.80952。任何人都可以解释这里有什么问题吗？

体积公式= 4/3（πxr ^ 3）

  #include< stdio.h> 
 
 int main（）
 
 
 {
 float radius = 0; 
浮动量; 
 float pie = 0; 
 
 printf（Enter radius）; 
 scanf（％f，& radius）; 
 
 pie = 22/7; 
 
 volume =（4 * pie * radius * radius * radius）/ 3; 
 printf（音量是％f，音量）; 
 
返回0; 
 
  

解决方案

c $ c> pie = 3.14; 而不是 pie = 22/7;

请记住：
（a）两个整数之间的算术运算总是返回一个整数。
（b）两个实数之间的算术运算总是返回一个实数。
（c）整数和实数之间的算术运算返回一个实数。

所以， pie = 22/7 将返回500.000000而不是523.80952。
，因此你也可以写 pie = 22.0 / 7 或 pie = 22 / 7.0 或 pie = 22.0 / 7.0 。这三个将返回原来的答案。

Im not getting correct answer with the following code below. Can anyone debug this code? When I input radius = 5, the answer I get is 500.000000 whereas the original answer should be 523.80952. Can anyone please explain what's wrong here?

Sphere volume formula =4/3(π x r^3)

#include <stdio.h>

int main()


    {
    float radius = 0;
    float volume;
    float pie = 0;

    printf("Enter radius");
    scanf("%f", &radius);

    pie = 22 / 7;

    volume = (4*pie*radius*radius*radius)/3;
    printf("the volume is %f", volume);

    return 0;
    }

解决方案

You can also write pie = 3.14 ; instead of pie = 22 / 7 ;

And keep in mind that: (a) Arithmetic operation between two integers always returns an integer. (b) Arithmetic operation between two real numbers always returns a real number. (c) Arithmetic operation between an integer and a real number returns a real number.

So, pie = 22 / 7 will return 500.000000 instead of 523.80952. therefore you can also write pie = 22.0 / 7 or pie = 22 / 7.0 or pie = 22.0 / 7.0. These three will return the original answer.

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