警告：为foreach（）提供了无效的参数 [英] Warning: Invalid argument supplied for foreach() in

问题描述

  $ results = mysql_query（select * from classpics）; 
 
 foreach（$ results as $ uno）{
 echo'< td valign =middlealign =center>< a class =neutralhref =。 ./images.php?id='。$ uno ['id']。'>< img src ='。$ uno ['thumbs']。'border =0/>< / A>'; 
 
  

解决方案 mysql_query 返回一个 资源id ，您应该获取数组：

  $ results = mysql_query select * from classpics）; 
 
 while（$ row = mysql_fetch_array（$ results））{
 echo'< td valign =middlealign =center>< a class =neutralhref =../ images.php？id ='。$ row ['id']。'>< img src ='。$ row ['thumbs']。'border =0/> ;< / A>'; 
} 
  

$results = mysql_query("select * from classpics");

foreach($results as $uno) {
    echo '<td valign="middle" align="center"><a class="neutral" href="../images.php?id=' . $uno['id'] . '"><img src="'. $uno['thumbs'].'" border="0" /></a>';
}

解决方案

The mysql_query returns a resource id, you should fetch an array:

$results = mysql_query("select * from classpics");

while($row = mysql_fetch_array($results)){
  echo '<td valign="middle" align="center"><a class="neutral" href="../images.php?id=' . $row['id'] . '"><img src="'. $row['thumbs'].'" border="0" /></a>';
}

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