如何把每个PHP的foreach值到每个jquery ajax [英] how to put each php foreach value into each jquery ajax

问题描述

foreach($data['data'] as $data){
    $count = $data['number'];
}

// $data['number']; will return some number like:

159809
359107
249178
... //10+ numbers

然后，如何将每个PHP foreach值放入每个 jquery ajax 中？ （把每个数字通过一个jQuery的Ajax，将有10 + Ajax调用，并返回所有的数据在一个div）。谢谢。

Then, how to put each php foreach value into each jquery ajax? (put every number via a jquery ajax, there will be 10+ ajax calls, and return all the data in one div). Thanks.

<script type="text/javascript">
jQuery(document).ready(function(){
    $.ajax({
        url: "process.php", 
        dataType: "html",
        type: 'POST', 
        data: "items=<?php echo $count; ?>", //each $count value in each ajax
        success: function(data){
            $("#result").html(data);
        }
    });
});
</script>
<div id="result"></div>

推荐答案

如果你真的想要一个独特的ajax调用每个$计数值，数据在#result div中返回：

If you really want a unique ajax call for each $count value, with the data returning in the #result div:

<script type="text/javascript">
    $(document).ready(function(){

<?php
foreach($data['data'] as $data){
    $count = $data['number'];
    ?>
      $.ajax({
        url: "process.php", 
        dataType: "html",
        type: 'POST', 
        data: "items=<?php echo $count; ?>",
        success: function(data){
            $("#result").append(data);
        }
      });
    <?php
}
?>

    });
</script>
<div id="result"></div>

但是，我强烈建议将值作为一个数组传递，只有一个ajax调用： p>

However, I would highly recommend passing the values as an array and having only one ajax call:

$count = array();
foreach($data['data'] as $data){
    $count[] = $data['number'];
}
$datacount = implode('-',$count);
?>

<script type="text/javascript">
    $(document).ready(function(){
      $.ajax({
        url: "process.php", 
        dataType: "html",
        type: 'POST', 
        data: "items=<?php echo $datacount; ?>",
        success: function(data){
            $("#result").append(data);
        }
      });
    });
</script>
<div id="result"></div>

在process.php的服务器端，可以 explode（' '，$ _ POST ['items']）然后通过它们进行foreach。

On the server side in process.php, you can explode('-',$_POST['items']) and then foreach through them.

这是完成它的另一种方法。它可以是json_encoded或许多其他方式。

This is just one other way to accomplish it... It could be json_encoded or many other ways.

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