XSLT-XPath：用于重新分组元素的每个路径规范 [英] XSLT-XPath: For-each path specification for re-grouping of elements

问题描述

我有我想要转换到另一个结构的XML文档。文档示例如下所示：

 < application> 
< contactPerson> 
< name> Dominik< / name> 
< countryCode> DE< / countryCode> 
< / contactPerson> 
< contactPerson> 
<名称> Dorothea< / name> 
< countryCode> DE< / countryCode> 
< / contactPerson> 
< contactPerson> 
< name> Fiona< / name> 
< countryCode> FR< / countryCode> 
< / contactPerson> 
< contactPerson> 
< name> Fabian< / name> 
< countryCode> FR< / countryCode> 
< / contactPerson> 
< contactPerson> 
<名称> Florian< / name> 
< countryCode> FR< / countryCode> 
< / contactPerson> 
< contactPerson> 
< name> Gabi< / name> 
< countryCode> GB< / countryCode> 
< / contactPerson> 
< contactPerson> 
<名称> Gert< / name> 
< countryCode> GB< / countryCode> 
< / contactPerson> 
< / application> 
  

现在我想要按照国家来分组元素，这意味着结果应该如下所示：

 < application> 
< memberState> 
< countryCode> De< / countryCode> 
< contactPerson> 
< name> Dominik< / name> 
< / contactPerson> 
< contactPerson> 
<名称> Dorothea< / name> 
< / contactPerson> 
< / memberState> 
< memberState> 
< countryCode> FR< / countryCode> 
< contactPerson> 
< name> Fiona< / name> 
< / contactPerson> 
< contactPerson> 
< name> Fabian< / name> 
< / contactPerson> 
< contactPerson> 
<名称> Florian< name> 
< / contactPerson> 
< / memberState> 
< memberState> 
< countryCode> GB< / countryCode> 
< contactPerson> 
< name> Gabi< / name> 
< / contactPerson> 
< contactPerson> 
<名称> Gert< / name> 
< / contactPerson> 
< / memberState> 
< / application> 
  

我正在使用XPath for-each模式来选择所有国家，但它不会执行它应该这样做。我的模式如下所示：

 < xsl：template match =/> 
< application> 
< xsl：for-each select =/ application / contactPerson / countryCode [not（。= preceding-sibling :: * / application / contactPerson / countryCode）]> 
< memberState> 
< countryCode> 
< xsl：value-of select =。/> 
< / countryCode> 
< contactPerson> 
< name> 
< xsl：value-of select =../ name/> 
< / name> 
< / contactPerson> 
< / memberState> 
< / xsl：for-each> 
< / application> 
< / xsl：template> 
  

该错误可能是XPath表达式中的某处不能编译的。我把它改成了以下内容：

 < xsl：for-each select =/ application / contactPerson / countryCode [not（。 =前同辈:: *）]> 
  

因为我觉得我已经在树的正确位置了。这个解决方案编译，但它并没有给我一个独特的国家列表，我打算使用之前的兄弟姐妹，而是完整的清单。

除此之外，我需要我的问题的解决方案，我会特别感谢帮助理解实际发生在这里。

1. 有可能给我的第二个解决方案的相对路径，还是我必须给每个完整的路径？
   
2. 我是在正确的轨道上作出一个独特的国家代码列表，或者一般
   
3. 
   
   $ b 是否使用XSLT实际实现了解决方案？

解决方案

您的XPath表达式几乎是正确的：



 < xsl：for-each 
 select =/ application / contactPerson / countryCode [not（。= preceding-sibling :: *）]> 
  

不工作的原因是countryCode没有兄弟关系。要找到以前的countryCodes，您需要向上移动一层，然后再移回：



 < xsl：for-each 
 select =/ application / contactPerson / countryCode [not（。= ../preceding-sibling::/countryCode)]\"> 
  

我相信应该成功遍历不同的countryCodes。



您对模板的修改应该可以工作。您需要另一个循环遍历每个国家/地区的所有人：



 < xsl：template match =/> 
< application> 
< xsl：for-each select =/ application / contactPerson / countryCode [not（。= .. / preceding-sibling :: * / countryCode）]> 
< memberState> 
< countryCode> 
< xsl：value-of select =。/> 
< / countryCode> 
< xsl：for-each select =/ application / contactPerson [countryCode = current（）]> 
< contactPerson> 
< name> 
< xsl：value-of select =name/> 
< / name> 
< / contactPerson> 
< / xsl：for-each> 
< / memberState> 
< / xsl：for-each> 
< / application> 
< / xsl：template> 
  




I have XML documents which I want to transfer into another structure. An example of a document looks as follows:

<application>
    <contactPerson>
        <name>Dominik</name>
        <countryCode>DE</countryCode>
    </contactPerson>
    <contactPerson>
        <name>Dorothea</name>
        <countryCode>DE</countryCode>
    </contactPerson>
    <contactPerson>
        <name>Fiona</name>
        <countryCode>FR</countryCode>
    </contactPerson>
    <contactPerson>
        <name>Fabian</name>
        <countryCode>FR</countryCode>
    </contactPerson>
    <contactPerson>
        <name>Florian</name>
        <countryCode>FR</countryCode>
    </contactPerson>
    <contactPerson>
        <name>Gabi</name>
        <countryCode>GB</countryCode>
    </contactPerson>
    <contactPerson>
        <name>Gert</name>
        <countryCode>GB</countryCode>
    </contactPerson>
</application>

Now what I want to do is group the elements by country, meaning the result should look like this:

<application>
    <memberState>
        <countryCode>De</countryCode>
        <contactPerson>
            <name>Dominik</name>
        </contactPerson>
        <contactPerson>
            <name>Dorothea</name>
        </contactPerson>
    </memberState>
    <memberState>
        <countryCode>FR</countryCode>
        <contactPerson>
            <name>Fiona</name>
        </contactPerson>
        <contactPerson>
            <name>Fabian</name>
        </contactPerson>
        <contactPerson>
            <name>Florian<name>
        </contactPerson>
    </memberState>
    <memberState>
        <countryCode>GB</countryCode>
        <contactPerson>
            <name>Gabi</name>
        </contactPerson>
        <contactPerson>
            <name>Gert</name>
        </contactPerson>
    </memberState>
</application>

I am using an XPath for-each pattern to select all countries, but it doesn't do what it is supposed to do. My pattern looks as follows:

  <xsl:template match="/">
    <application>
      <xsl:for-each select="/application/contactPerson/countryCode[not(.=preceding-sibling::*/application/contactPerson/countryCode)]">
        <memberState>
          <countryCode>
            <xsl:value-of select="."/>
          </countryCode>
          <contactPerson>
            <name>
              <xsl:value-of select="../name"/>
            </name>
          </contactPerson>
        </memberState>
      </xsl:for-each>
    </application>
  </xsl:template>

The error is probably somewhere in the XPath expression which does not compile. I changed it to the following

<xsl:for-each select="/application/contactPerson/countryCode[not(.=preceding-sibling::*)]">

because I think I am already at the right position of my tree. This solution compiles, but it doesn't give me a unique list of countries as I intended by using "preceding-sibling" but the complete list instead.

Besides that I need the solution to my problem, I would be especially thankful for some help on understanding what is actually happening here.

1. Is it possible to give a relative path as in my second solution or do I have to give the complete path each time?
2. Am I on the right track for making a unique list of country codes, or would that generally be implemented differently?
3. Is the solution I am looking for actually implementable with XSLT?

I appreciate your help very much.

解决方案

Your XPath expression was almost correct:

<xsl:for-each 
    select="/application/contactPerson/countryCode[not(.=preceding-sibling::*)]"> 

The reason it didn't work is that countryCode doesn't have any siblings. To find the previous countryCodes, you need to move up one level and then back down:

<xsl:for-each 
    select="/application/contactPerson/countryCode[not(. = ../preceding-sibling::*/countryCode)]"> 

I believe that should successfully iterate through the distinct countryCodes.

This modification to your template should work. You needed another loop to iterate through all the people for each country:

<xsl:template match="/">
    <application>
      <xsl:for-each select="/application/contactPerson/countryCode[not(.=../preceding-sibling::*/countryCode)]">
        <memberState>
          <countryCode>
            <xsl:value-of select="."/>
          </countryCode>
          <xsl:for-each select="/application/contactPerson[countryCode = current()]">
          <contactPerson>
            <name>
              <xsl:value-of select="name"/>
            </name>
          </contactPerson>
          </xsl:for-each>
        </memberState>
      </xsl:for-each>
    </application>
  </xsl:template>

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