Java重复字符 [英] java repeat character

问题描述

我是一个java初学者，请记住这一点。我必须制作一个读取数字的程序，然后显示感叹号！。

这是我的：

  import java.util.Scanner; 
 import java.io.PrintStream; 
 
 class E_HerhaalKarakter1 {
 
 PrintStream out; 
 
 E_HerhaalKarakter1（）{
 out = new PrintStream（System.out）; 
 
 
 String printUitroeptekens（int aantal）{
 String output =！ 
 
 for（int i = 0; i< = aantal; i ++）{
 output.concat（！）; 
} 
返回输出; 
} 
 
 void start（）{
 Scanner in = new Scanner（System.in）; 
 
 out.printf（Hoeveel uitroeptekens wilt weergeven？\\\
）; $（b）b 
 if（in.hasNext（））{
 out.printf（baldbla）; 
 printUitroeptekens（in.nextInt（））; 
 out.printf（％s，output）; 
 
 
 
 public static void main（String [] argv）{
 new E_HerhaalKarakter1（）。start（）; 
 
 
 
 
 $ b $ p 
 $ p 
 <如果你确实需要创建一个包含X个感叹号的字符串，那么这里有一个方法可以不用重复的连接：
 





  char [] exmarks = new char [aantal]; 
 Arrays.fill（exmarks，'！'）; 
 String exmarksString = new String（exmarks）; 
  




I am a java beginner, please keep that in mind. I have to make a program that reads a number, and then displays that amount of exclamation mark "!".

This is what i have:

import java.util.Scanner;
import java.io.PrintStream;

class E_HerhaalKarakter1 {

 PrintStream out;

 E_HerhaalKarakter1 () {
  out = new PrintStream(System.out);
 }

 String printUitroeptekens (int aantal) {
  String output = "!"

  for (int i = 0; i <= aantal; i++) {
   output.concat("!");
  }
  return output;
 }

 void start () {
  Scanner in = new Scanner(System.in);

  out.printf("Hoeveel uitroeptekens wilt u weergeven?\n");

  if(in.hasNext()) {
   out.printf("baldbla");
   printUitroeptekens(in.nextInt());
   out.printf("%s",output);
  }
 }

 public static void main (String[] argv) {
  new E_HerhaalKarakter1().start();
 }
}

Thank you

解决方案

If you do actually have the requirement to create a string which contains X number of exclamation marks, then here's a way to do it without repeated concatenation:

char[] exmarks = new char[aantal];
Arrays.fill(exmarks, '!');
String exmarksString = new String(exmarks);

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