获取循环内的下一个值 [英] Getting the next value within for loop

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本文介绍了获取循环内的下一个值的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在用Python编写一个程序,它从文件中读取银行数据,并将其存储在数据结构中,以备日后输出。

我有一个列表存储诸如

  D,520,W,20,D,100 

其中信是交易类型(取款或存款),数字是金额。



基本上我想要做的是:

我有一个for循环来计算余额,但是我无法进入下一个元素。如果项目=='D':
balance = balance + int(NEXT_ITEM),那么

$ b pre $
if item =='W':
balance = balance - int(NEXT_ITEM)

感谢您的帮助

解决方案

  data ='D,520,W ,20,D,100'.split(',')

def pair(lst):
it iter(lst)
return zip(it,it)

b alance = 0
for trans,amt成对(数据):
if trans =='D':
balance + = int(amt)
else:
balance - = int(amt)
print(balance)


I am writing a program in Python that reads in bank data from a file and stores it in data structures for output at a later time.

I have a list that stores the transactions like

D,520,W,20,D,100

Where the letter is the transaction type (Withdrawl or Deposit) and the numbers are the amount.

I have a for loop that will calculate the balance, but I am having trouble getting to the next element.

Essentially what I want to do is:

for item in theList:
    if item == 'D':
        balance = balance + int(NEXT_ITEM)
    if item == 'W':
        balance = balance - int(NEXT_ITEM)

Thanks for the help

解决方案

data = 'D,520,W,20,D,100'.split(',')

def pairs(lst):
    it = iter(lst)
    return zip(it, it)

balance = 0
for trans,amt in pairs(data):
    if trans == 'D':
        balance += int(amt)
    else:
        balance -= int(amt)
print(balance)

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