Javascript - 数组中使用循环的最大数字 [英] Javascript - biggest number from array using loop
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问题描述
var num = []; (i = 0; i <10; i ++){
num [i] = parseInt(prompt(Unesite broj+(i + 1)+。));
}
var maximum = 0;
for(i = 0; i if(num [i]>最大){
largest = num [i]
$ b console.log(最大的数字是+最大的);
解决方案
首先,我们没有看到数字,代码假设最大值为0或更大:
var maximum = 0;
我们将查看列表中的每个数字:
for(i = 0; i
目前的数字是否大于我们所见过的最大数字?
if(num [如果是这样的话,那就是 new 最大的最大){
数字
最大=数字[i];
code $
当循环完成时,最大的
包含我们沿途看到的最大的数字。
Can somebody please explain how this code gets which number from array is the biggest?
var num = [];
for( var i = 0; i < 10; i++ ) {
num[i] = parseInt( prompt("Unesite broj " + (i+1) + "." ) );
}
var biggest = 0;
for(i=0; i < num.length; i++ ) {
if( num[i] > biggest ) {
biggest = num[i];
}
}
console.log("The biggest number is " + biggest );
解决方案 To start, we've seen no numbers, and the code assumest the biggest is 0 or larger:
var biggest = 0;
We'll look at each number in the list:
for(i=0; i < num.length; i++ ) {
Is the current number bigger than the biggest we've seen?
if( num[i] > biggest ) {
If so, it's the new biggest number
biggest = num[i];
}
}
When the loop is done, biggest
contains the largest number we saw along the way.
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