如何在Python屏幕上绘制方格旗? [英] How to draw a checkered flag to the Python screen?
问题描述
$ b
1 问题: 。询问用户的方格旗(n)的大小。
2.在屏幕上绘制一个n×n的网格。
3.对于i = 0,2,4,...,62:
4. row = i // n
5. offset = row%2
6。 col =(i%n)+ offset
请复制并粘贴链接,参见输出: http://www.awesomescreenshot.com/image/45977/12eaef67de44c2b291ecd47fe8d10135
我实现了伪代码,但是我需要一些帮助。我一直得到这个错误: row,col = findGrid(x)
TypeError:'int'object is not iterable $我的程序:
from turtle import * c $ c
$ b
$ b def size():
size = eval(input(请输入格子旗的大小:))
返回大小
def draw(n):
wn = Screen()
wn.setworldcoordinates(-1,-1,10,10)
pen = Turtle()
(0,n + 1):
pen.up()
pen.goto(0,i)
pen.down()
pen.forward(n)
pen.left(90)
在范围内(0,n + 1):
pen.up()
pen.goto(i,0)$ ($)
$
$ find $($)
$行= i // n
偏移量=行%2
col =(i%n)+偏移量
返回行
返回列
def fillSquare(x,y):
pen = Turtle()
pen.hideturtle()
pen.speed(10)
pen.up()
pen.goto(x ,y)
pen.fillcolor(black)
pen.begin_fill()
def main():
x = size()
y = draw(x)
row,col = findGrid(x)
f = fillSquare(row,col)
$ b main()
如果您想要返回
以某种方式结合他们。如果你这样做的话:
$ $ $ $ $ $ $ c $ return $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ pre>
程序将返回
行
然后退出函数,因为这就是 return
所做的。在执行第一个 return
之后什么都不会执行。试试这个:
return row,col
返回的值是一个元组
,这正是您需要执行的操作 row,col = findGrid(x)
出现在你的 main()
中。而不是计算单个 int
, findGrid(x)
将取代一个元组
包含两个 int
s,Python可以迭代元组
来将每个值放入指定的变量行
和 col
。
由Python解释器生成的消息通常是相当丰富的。在这种情况下,当它说 int对象不可迭代
时,可以打赌它试图迭代 int
可以理解的是失败了。所有你需要做的就是推断出错误的语句是在哪里寻找一个可迭代的,找到产生有问题的表达式( findGrid(x)
),并检查它是否是返回一个 int
或者一个可迭代的。
QUESTION: Implement the following pseudocode to draw a checkered flag to the screen.
1. Ask the user for the size of the checkered flag (n).
2. Draw an n x n grid to the screen.
3. For i = 0,2,4,...,62:
4. row = i // n
5. offset = row % 2
6. col = (i % n) + offset
Please copy and paste the link see the ouput: http://www.awesomescreenshot.com/image/45977/12eaef67de44c2b291ecd47fe8d10135
I implemented the pseudocode, but I need some help. I am keep getting this error: row, col = findGrid(x)
TypeError: 'int' object is not iterable
My program:
from turtle import*
def size():
size = eval(input("Please enter the size of the checkered flag: "))
return size
def draw(n):
wn = Screen()
wn.setworldcoordinates(-1,-1,10,10)
pen = Turtle()
for i in range(0,n+1):
pen.up()
pen.goto(0,i)
pen.down()
pen.forward(n)
pen.left(90)
for i in range(0,n+1):
pen.up()
pen.goto(i,0)
pen.down()
pen.forward(n)
def findGrid(n):
for i in range(0,63):
row = i // n
offset = row % 2
col = (i % n) + offset
return row
return col
def fillSquare(x,y):
pen = Turtle()
pen.hideturtle()
pen.speed(10)
pen.up()
pen.goto(x,y)
pen.fillcolor("black")
pen.begin_fill()
def main():
x = size()
y = draw(x)
row, col = findGrid(x)
f = fillSquare(row, col)
main()
If you want to return
two values, you must combine them in some way. If you do this:
return row
return col
the program will return
the row
and then exit the function, because that's what return
does. Nothing after the first return
will ever be executed. Try this instead:
return row, col
The returned value will be a tuple
, which is exactly what you need to carry out row, col = findGrid(x)
as appears in your main()
. Instead of evaluating to a single int
, findGrid(x)
will instead evaluate to a tuple
containing two int
s, and Python can iterate over that tuple
to place each value into the specified variables row
and col
.
The error messages generated by the Python interpreter are usually pretty informative. In this case, when it says int object is not iterable
, you can bet that it tried to iterate over an int
and understandably failed. All you have to do then is deduce where the erroneous statement in question is looking for an iterable, find what produces the problematic expression (findGrid(x)
), and inspect whether it returns an int
or an iterable.
这篇关于如何在Python屏幕上绘制方格旗?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!