fmt.Sprintf传递参数数组 [英] fmt.Sprintf passing an array of arguments

问题描述

对不起，基本的问题。我想传递一个片段作为 fmt.Sprintf 的参数。就像这样：

  values：= [] string {foo，bar，baz} 
结果：= fmt.Sprintf（％s％s％s，values ...）
  

结果会是 foobarbaz ，但这显然不起作用。

格式比这更复杂，所以一个简单的连接不会这样做）

所以问题是：如果我有数组，那么我怎样才能把它作为将参数分隔到 fmt.Sprintf ？或者：我可以调用一个函数传递一个参数列表？

解决方案

当你在IRC上发现，这将工作：

$ p $ values：= [] interface {} {foo，bar，baz}
结果：= fmt.Sprintf（％s％s％s，values ...）


您的原始代码不起作用，因为 fmt.Sprintf 接受 []界面{} 和 [] string 无法隐式或显式地转换为该类型。

Sorry for the basic question. I'd like to pass a slice as arguments to fmt.Sprintf. Something like this:

values := []string{"foo", "bar", "baz"}
result := fmt.Sprintf("%s%s%s", values...)

And the result would be foobarbaz, but this obviously doesn't work.

(the string I want to format is more complicated than that, so a simple concatenation won't do it :)

So the question is: if I have am array, how can I pass it as separated arguments to fmt.Sprintf? Or: can I call a function passing an list of arguments in Go?

解决方案

As you found out on IRC, this will work:

values := []interface{}{"foo", "bar", "baz"}
result := fmt.Sprintf("%s%s%s", values...)

Your original code doesn't work because fmt.Sprintf accepts a []interface{} and []string can't be converted to that type, implicitly or explicitly.

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