如何在Java中将区域设置格式的数字转换为BigInteger？ [英] How to convert locale formatted number to BigInteger in Java?

问题描述

我搜索了很多，但没有帮助我:(假设我需要将12.090.129.019.201.920.192.091.029.102.901.920.192.019.201.920（在葡萄牙语组分隔符：。）转换为BigInteger值。如何转换？我尝试使用NumberFormat，DecimalFormat和没有任何工作，或者我没有正确的方式:(

解决方案

获取 NumberFormat 实例为葡萄牙语 Locale ，然后解析这个数字，这也将处理特定于locale的小数点分隔符。

  NumberFormat nf = NumberFormat.getNumberInstance（new Locale（pt，PT））; 
 DecimalFormat df =（DecimalFormat）nf; 
 df.setParseBigDecimal（true）; 
 BigDecimal decimal =（BigDecimal）df.parse（12.090.129.019.201.920.192.091.029.102.901.9 20.192.019.201.920\" ）; 
 BigInteger big = decimal.toBigInteger（）; 
  

DEMO 。

I searched a lot but nothing helped me :( Suppose I need convert 12.090.129.019.201.920.192.091.029.102.901.920.192.019.201.920 (in Portuguese group separator: .) to BigInteger value. How to do that conversion? I tried use NumberFormat, DecimalFormat and nothing works or I didn't on right way :(

解决方案

Get a NumberFormat instance for a Portuguese Locale, and then parse the number with it. This will also handle locale-specific decimal separators.

NumberFormat nf = NumberFormat.getNumberInstance(new Locale("pt", "PT"));
DecimalFormat df = (DecimalFormat)nf;
df.setParseBigDecimal(true);
BigDecimal decimal = (BigDecimal)df.parse("12.090.129.019.201.920.192.091.029.102.901.920.192.019.201.920");
BigInteger big = decimal.toBigInteger();

DEMO.

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