PHP表单动作PHP自我 [英] php form action php self
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问题描述
< form name =form1id =mainFormmethod = postenctype =multipart / form-dataaction =<?php echo $ _SERVER ['PHP_SELF'];?>>
在表单操作中,我想使用页面名称带参数。如 house.php?p_id = 10111
。但$ _SERVER ['PHP_SELF']只给出 house.php
(我的页面完整url为 house.php?p_id = 10111
这样)请帮我解决这个问题。感谢。
解决方案
如何将它留空,这有什么不妥?
< form name =form1id =mainFormmethod =postenctype =multipart / form-dataaction =>
< / form>
另外,您可以省略操作属性,它将按预期工作。
I have a php form like this.
<form name="form1" id="mainForm" method="post"enctype="multipart/form-data" action="<?php echo $_SERVER['PHP_SELF'];?>">
</form
In form action I want to use page name with parameters. like house.php?p_id=10111
. But $_SERVER['PHP_SELF'] gives only the house.php
(My page full url is house.php?p_id=10111
like this) Please help me to solve this problem. thanks.
解决方案
How about leaving it empty, what is wrong with that?
<form name="form1" id="mainForm" method="post" enctype="multipart/form-data" action="">
</form>
Also, you can omit the action attribute and it will work as expected.
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