在表单提交时传递当前网址 [英] Pass current URL on form submit

问题描述

作为将值添加到查询字符串的延续一个URL ，我有一个搜索框，将添加额外的参数到当前的URL。

  http：// example.com/?s=original+new+arguments&fq=category 
  

表单代码看起来像这：

 < form id =FilterSearchmethod =getaction =http://example.com/ search_result.php> 
  

其中search_result.php只是我创建的一个新页面，用于解析使用新URL的提交和重定向。

如何将原始网址传递给search_result.php以便我可以操纵网址？

编辑＃1 ：我添加了一个隐藏的输入：

 <？php $ current_url = $ _SERVER [HTTP_HOST]。 $ _SERVER [ REQUEST_URI]; ？> 
< input type =hiddenname =current_urlvalue =<？php $ current_url;？> /> 
< input name =sendid =sendtype =submitvalue =Search/> 
  

我的输出仅将参数添加到提交页面（search_result.php），而不是预期的查询<$ p
$ b

 <？php 
 if（isset（$ _ GET ['send']））{
 $ searchField = urlencode（$ _ GET ['SearchField']）; 
 $ location = $ _GET ['current_url']; 
 $ location = preg_replace（$ location，'/（[？&] s =）（[^&] +）/'，'$ 1 $ 2 +'。$ searchField）; 
 header（'Location：'。$ location）; 
} 
？> 
  

我要么传错错误，要么弄错了，或者两者兼而有之！

编辑＃2 ：输出网址如下：

  http： //example.com/wp-content/themes/child_theme/search_result.php?SearchField=newTerm&current_url=www.example.com%2F%3Fs%3DoldTerm%26searchsubmit%3D&send=Search 
  

编辑＃3
我回应了输出网址，它是正确的。我摆脱了preg_match，看看我是否可以在处理表单时获得相同的URL。有趣的是，我找不到一个页面。我决定添加 http：// 标题并且它工作：

  header（'Location： HTTP：//'.$location）; 
  

因此，我相信这里唯一错误的是preg_replace。

解决方案

我认为你正在寻找隐藏的输入。

类似这样：

 < input type =hiddenname =current_urlvalue =（当前网址）/> 
  

然后像访问任何其他$ _GET或$ _POST参数一样访问它。

---

编辑回复编辑：

您可以 echo $ location;在这行后面：

  $ location = $ _GET ['current_url']; 
  

让我知道输出是什么？这会告诉我们它是否被错误地传递或处理不正确。

As a continuation of Adding Values to a Query String in a URL, I have a search box that will add additional arguments to the current URL.

http://example.com/?s=original+new+arguments&fq=category

The form code looks like this:

<form id="FilterSearch" method="get" action="http://example.com/search_result.php">

Where search_result.php is just a new page I created to parse the submit and redirect using the new URL.

How can I pass the original URL to search_result.php so that I can then manipulate the URL?

EDIT #1 : I added a hidden input:

<?php $current_url = $_SERVER["HTTP_HOST"] . $_SERVER["REQUEST_URI"]; ?>
<input type="hidden" name="current_url" value="<?php $current_url; ?>" />
<input name="send" id="send" type="submit" value="Search" />

My output is only adding the arguments to the submission page (search_result.php) and not the intended query page.

<?php
if (isset($_GET['send'])){
                $searchField = urlencode($_GET['SearchField']);
                $location =  $_GET['current_url'];
                $location = preg_replace($location, '/([?&]s=)([^&]+)/', '$1$2+'.$searchField);
                header('Location: '.$location);
                }
?>

I'm either passing them wrong or getting them wrong or both!

EDIT #2 : Output URL is like:

http://example.com/wp-content/themes/child_theme/search_result.php?SearchField=newTerm&current_url=www.example.com%2F%3Fs%3DoldTerm%26searchsubmit%3D&send=Search

EDIT #3 I echoed the output URL and it's correct. I got rid of the preg_match just to see if I could get the same URL when I processed the form. Interestingly, I got a page not found. I decided to add http:// the header and it worked:

header('Location: http://'.$location);

So therefore, I believe that the only thing wrong here is the preg_replace.

解决方案

I think you're looking for the hidden input.

Something like this:

<input type="hidden" name="current_url" value="(Current URL here)" />

Then access it just like you would any other $_GET or $_POST parameter.

---

EDIT to respond to edits:

Could you echo $location; die; after this line:

$location =  $_GET['current_url'];

and let me know what the output is? This will tell us whether it's being passed incorrectly or processed incorrectly.

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